12
The middle two numbers are 8 and 10 so the median is 9.
8.5
If a set of numbers is arranged in ascending or descending order the median is the value which lies halfway along the series. 9-6-5-0-6-11-10 when placed in ascending order becomes 0-5-6-6-9-10-11. The median is therefore 6. Note : When there are an even number of values the median is the mean of the middle two values.
Median of the set = arithmetic mean of 8 and 9 = 8.5
1 5 6 8 10 11 12 13 The median (or middle number) is 9.
First, to find median put numbers in order so: 5, 5, 6, 7, 8, 9, 10, ( 10, 12 ,) 14, 15, 17, 18, 18, 18, 20 10 + 12= 22 divided by 2= 11, the median is 11
12
The middle two numbers are 8 and 10 so the median is 9.
12
8.5
If a set of numbers is arranged in ascending or descending order the median is the value which lies halfway along the series. 9-6-5-0-6-11-10 when placed in ascending order becomes 0-5-6-6-9-10-11. The median is therefore 6. Note : When there are an even number of values the median is the mean of the middle two values.
11
Median of the set = arithmetic mean of 8 and 9 = 8.5
These are your 5 numbers: X X X X X the median (the middle number of a row) is 11, that means: X X 11 X X the mode (the most frequent number in a row) is 12, that means: X X 11 12 12 the mean (the average) is 10, that means: (X+X+11+12+12)/5=10 or: X+X+11+12+12=50 or: X+X=50-12-12-11 or: X+X=15 so the remaining numbers must be 15 combined, and lower then 11, that means they can be: 5 and 10 6 and 9 7 and 8 so you have 3 possible solutions: 5 10 11 12 12 6 9 11 12 12 7 8 11 12 12
Mean: 7 Median: 6 Mode: 1, 9, 4, 7, 5, 3, 16, 11
6 7 8 8 8 10 11 11 11 12 13 minimum-6 median-10 range-13-6=7 modes-8,11