To find the middle term of the product ((x + 5)(x + 2)), we first expand the expression. This gives us (x^2 + 2x + 5x + 10), which simplifies to (x^2 + 7x + 10). The middle term is the linear term, which is (7x).
By splitting the Middle Term, 5X2 + 25X + 4X +20 5X(X+5) + 4(X+5) (5X+4)(X+5)
The expression "5x plus 12" can be written mathematically as (5x + 12). This represents a linear equation where (5x) is the term involving the variable (x), and (12) is a constant term. If you need to evaluate it for a specific value of (x), you would substitute that value into the expression.
y - 5x
5x plus 3 does equal 3 plus 5x; commutative law.
x + 3x + 5x is effectively a single term. A single term cannot have a greatest COMMON factor where the word common implies that it refers to two or more terms.
By splitting the Middle Term, 5X2 + 25X + 4X +20 5X(X+5) + 4(X+5) (5X+4)(X+5)
The expression "5x plus 12" can be written mathematically as (5x + 12). This represents a linear equation where (5x) is the term involving the variable (x), and (12) is a constant term. If you need to evaluate it for a specific value of (x), you would substitute that value into the expression.
y - 5x
Since 5x is a factor of both terms, divide it. 5x3 + 5x = 5x(x2 + 1)
5x plus 3 does equal 3 plus 5x; commutative law.
9 is the constant. 5 is the coefficient of the variable term. X is the variable term.
x + 3x + 5x is effectively a single term. A single term cannot have a greatest COMMON factor where the word common implies that it refers to two or more terms.
The expression (-5x^3 + 10x^2) represents a polynomial in terms of (x). It consists of two terms: (-5x^3), which is a cubic term, and (10x^2), which is a quadratic term. This polynomial can be factored as ( -5x^2(x - 2) ).
-10x + 5x = -5x
5x
You can do this by trying to find a pair of numbers that that have a sum which is equal to the coefficient of the middle term, and a product that is equal to the product of the coefficients of the first and last term. In other words, you want two numbers, "a" and "b" which add up to 5, and which have a product of -24: a + b = 5 a × b = -24 In this case, the numbers we need would be eight and negative three. We can then plug them into our equation, by splitting the middle term into the sum of those two numbers: x2 + 5x - 24 = x2 + 8x - 3x - 24 Now we can take pairs of those terms, and divide by common factors: = x(x + 8) - 3(x + 8) And finally, group like terms: = (x - 3)(x + 8)
x=6