a line segment has only one midpoint "C" but the two sections AC and CE can have their own midpoint "B" and "D" and so on... A B C D E
the midpoint of
The midpoint is (0, 1)
Each coordinate of the midpoint of a line segment is the average of the correspondingcoordinates of the end points.'x' of the midpoint = average of 'x' of the endpoints'y' of the midpoint = average of 'y' of the endpointsFor segment GF, you only need the coordinates of 'G' and 'F'.G . . . (b, 0)F . . . (3b, 2b)'x' of the midpoint = 1/2 (b + 3b) = 1/2 (4b) = 2b'y' of the midpoint = 1/2 (0 + 2b) = 1/2 (2b) = bCoordinates of the midpoint . . . (2b, b)
midpoint: (x1+x2/2 , y1+y2/2) quadratic: -b plus or minus square root b squared minus 4ac divided by 2a
The coordinate of what?
a line segment has only one midpoint "C" but the two sections AC and CE can have their own midpoint "B" and "D" and so on... A B C D E
the midpoint (apex) Between A and B (Apex)
the midpoint of
If AC = 10 units and D is the midpoint of AC then AD = AC/2 = 5 units!
The 'x' coordinate of B is the average of the 'x' coordinates of A and C. The 'y' coordinate of B is the average of the 'y' coordinates of A and C.
16cm
C is the midpoint of Ab . then AC = BC. So AC= CB.
It is the midpoint of the class interval. I.e let b=the highest number in the class, a = the lowest number in the class. The midpoint is (a+ 1/2(b-a)).
the midpoint of AB.
The midpoint is (0, 1)
Each coordinate of the midpoint of a line segment is the average of the correspondingcoordinates of the end points.'x' of the midpoint = average of 'x' of the endpoints'y' of the midpoint = average of 'y' of the endpointsFor segment GF, you only need the coordinates of 'G' and 'F'.G . . . (b, 0)F . . . (3b, 2b)'x' of the midpoint = 1/2 (b + 3b) = 1/2 (4b) = 2b'y' of the midpoint = 1/2 (0 + 2b) = 1/2 (2b) = bCoordinates of the midpoint . . . (2b, b)