16cm
If 2 segments have the same length they are known as 'congruent segments' IE: segment AB=segment AC (or AB=AC) then AB @ AC (or AB is congruent to AC)
sqrt(ab^2 + bc^2)
Ad < dbad < cbad + dc = cbDC + CB = DBAD < CB
Assuming that AB and AC are straight lines, the answer depends on the angle between AB and AC. Depending on that, BC can have any value in the range (22, 46).
There are some missing terms. First of all, I assume that A, B, and C are collinear and that B is between A and C.If this is true then AC-AB=BC by the whole is the sum of its parts theorem.24-20=4Otherwise, all that can be said about BC is that it's length is between AC-AB = 4 and AC+AB = 44 units.
C is the midpoint of Ab . then AC = BC. So AC= CB.
the midpoint of AB.
the midpoint of
the midpoint (apex) Between A and B (Apex)
If 2 segments have the same length they are known as 'congruent segments' IE: segment AB=segment AC (or AB=AC) then AB @ AC (or AB is congruent to AC)
sqrt(ab^2 + bc^2)
Ad < dbad < cbad + dc = cbDC + CB = DBAD < CB
Assuming that AB and AC are straight lines, the answer depends on the angle between AB and AC. Depending on that, BC can have any value in the range (22, 46).
36/√3
The length is sqrt(61) units.
By use of the sine rule: sin A / BC = sin B / AC = sin C / AB Angles B and C are known, as is length AC, so: sin B / AC = sin C / AB AB = AC x sin C / sin B AB = 17cm x sin 24 / sin 95 ~= 6.94cm The ratios for the sine rule can also be given the other way up: BC / sin A = AC / sin B = AB / sin C (I learnt the rule the first way.) Further, if r is the radius of the triangle's circumcircle, then: sin A / BC = 1/2r or BC / sin A = 2r
Find the length of each sideside ab and bc differ in length by 10cm and the side ac and bc differ in length 3cmfind the lenght of each sideperimeter of a triangle abc is 103cm?