( -2 , 0 )
Points: (0, 5) and (3, 0) Midpoint: (1.5, 2.5) Slope: -5/3 Perpendicular slope: 3/5 Perpendicular equation: y--5 = 3/5(x--3) => 5y = 3x-16 Distance is the square root of (1.5--3)^2+(2.5--5)^2 = 8.746 to three decimal places
It is (-3 + 5)/2 = 1.
If you mean points of (-1, 7) and (-3, 3) then the midpoint is at (-2, 5)
If the end points of the line segment are at (3, 5) and (2, 2) then the midpoint is at (2.5, 3.5)
( -2 , 0 )
Midpoint of (3, -6) and (-5, 2) = [(3-5)/2, (-6+2)/2] = (-1, -2)
Points: (0, 5) and (3, 0) Midpoint: (1.5, 2.5) Slope: -5/3 Perpendicular slope: 3/5 Perpendicular equation: y--5 = 3/5(x--3) => 5y = 3x-16 Distance is the square root of (1.5--3)^2+(2.5--5)^2 = 8.746 to three decimal places
It is (-3 + 5)/2 = 1.
If you mean points of (-1, 7) and (-3, 3) then the midpoint is at (-2, 5)
If the end points of the line segment are at (3, 5) and (2, 2) then the midpoint is at (2.5, 3.5)
-1 + -2 = -3-3/2 = -1.54 + -9 = -5-5/2 = -2.5So the midpoint = (-11/2, -21/2)
End points: (-3, 5) and 2, -1) Midpoint: (-3+2)/2 and (-1+5)/2 = (-1/2, 2)
(5/2,11/2)
Points:(4, 3) and (10, -5) Midpoint: (4+10)/2, (3-5)/2 = (7, -1)
Let the point A (x1, y1) = (2, 3) and B (x2, y2) = (4, 7). The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2] = [(2 + 4)/2, (3 + 7)/2] = [(6/2), (10/2)] = (3, 5) Thus, the midpoint is (3, 5).
If you mean endpoints of (1, 7) and (3, 3) then the midpoint is at (2, 5).