( -0.5, -2.5)
( -2 , 0 )
To find the midpoint of the segment connecting points A (-5) and D (0), you can use the midpoint formula, which is ((x_1 + x_2)/2). Here, (x_1 = -5) and (x_2 = 0). Thus, the midpoint is ((-5 + 0)/2 = -2.5). Therefore, the coordinate of the midpoint is (-2.5).
To find the midpoint of a segment with endpoints (3, 1) and (5, 3), you can use the midpoint formula: ((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})). Plugging in the values, the midpoint is ((\frac{3 + 5}{2}, \frac{1 + 3}{2}) = (4, 2)). Thus, the midpoint of the segment is (4, 2).
It is (-3 + 5)/2 = 1.
Points: (0, 5) and (3, 0) Midpoint: (1.5, 2.5) Slope: -5/3 Perpendicular slope: 3/5 Perpendicular equation: y--5 = 3/5(x--3) => 5y = 3x-16 Distance is the square root of (1.5--3)^2+(2.5--5)^2 = 8.746 to three decimal places
( -2 , 0 )
To find the midpoint of the segment connecting points A (-5) and D (0), you can use the midpoint formula, which is ((x_1 + x_2)/2). Here, (x_1 = -5) and (x_2 = 0). Thus, the midpoint is ((-5 + 0)/2 = -2.5). Therefore, the coordinate of the midpoint is (-2.5).
Midpoint of (3, -6) and (-5, 2) = [(3-5)/2, (-6+2)/2] = (-1, -2)
It is (-3 + 5)/2 = 1.
Points: (0, 5) and (3, 0) Midpoint: (1.5, 2.5) Slope: -5/3 Perpendicular slope: 3/5 Perpendicular equation: y--5 = 3/5(x--3) => 5y = 3x-16 Distance is the square root of (1.5--3)^2+(2.5--5)^2 = 8.746 to three decimal places
If you mean points of (-1, 7) and (-3, 3) then the midpoint is at (-2, 5)
If the end points of the line segment are at (3, 5) and (2, 2) then the midpoint is at (2.5, 3.5)
-1 + -2 = -3-3/2 = -1.54 + -9 = -5-5/2 = -2.5So the midpoint = (-11/2, -21/2)
End points: (-3, 5) and 2, -1) Midpoint: (-3+2)/2 and (-1+5)/2 = (-1/2, 2)
(5/2,11/2)
Points:(4, 3) and (10, -5) Midpoint: (4+10)/2, (3-5)/2 = (7, -1)
To find the midpoint of points P(5, -3) and Q(2, 4), use the midpoint formula: ((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})). This gives the midpoint as ((\frac{5 + 2}{2}, \frac{-3 + 4}{2}) = (\frac{7}{2}, \frac{1}{2})) or (3.5, 0.5). Since the x-coordinate is positive and the y-coordinate is positive, the midpoint lies in the first quadrant.