(5/2,11/2)
The midpoint of a line segment with endpoints at -4, 15 and 22, 3 is (9,9).
The midpoint of the line segment of (7, 2) and (2, 4) is at (4.5, 3)
(9, 2)
The mid point is at the mean average of each of the coordinates: The midpoint between A (6,3) and and B (8,1) is (6+8/2, 3+1/2) = (7, 2)
It is the midpoint of the class interval. I.e let b=the highest number in the class, a = the lowest number in the class. The midpoint is (a+ 1/2(b-a)).
The midpoint is at (3, 4)
The midpoint of a line segment with endpoints at -4, 15 and 22, 3 is (9,9).
Let the point A (x1, y1) = (2, 3) and B (x2, y2) = (4, 7). The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2] = [(2 + 4)/2, (3 + 7)/2] = [(6/2), (10/2)] = (3, 5) Thus, the midpoint is (3, 5).
The coordinates of point B can be calculated using the midpoint formula. The midpoint formula is used to find the midpoint of two points, and is calculated by taking the average of the x-coordinates and the average of the y-coordinates. In this case, we are given the midpoint of AB, which is (-2, -4). We also know the coordinates of point A, which are (-3, -5). Using the midpoint formula, we can calculate the x-coordinate of point B by taking the average of the x-coordinates of points A and M. This is (-3 + -2)/2 = -2.5. We can calculate the y-coordinate of point B in a similar way. This is (-5 + -4)/2 = -4.5. Therefore, the coordinates of point B are (-2.5, -4.5).
The midpoint of the line segment of (7, 2) and (2, 4) is at (4.5, 3)
(9, 2)
The midpoint is (0, 1)
The mid point is at the mean average of each of the coordinates: The midpoint between A (6,3) and and B (8,1) is (6+8/2, 3+1/2) = (7, 2)
An example of a midpoint is the point that divides a line segment into two equal parts. For instance, if a line segment connects the points A(2, 3) and B(6, 7) in a coordinate plane, the midpoint M can be calculated using the formula M = ((x1 + x2)/2, (y1 + y2)/2). In this case, the midpoint M would be (4, 5).
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
To find the midpoint of points A (45) and B (-2, -3), you can use the midpoint formula: ( M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) ). Here, A seems to have only one coordinate, which might be a mistake. Assuming A is (45, 0), the midpoint would be ( M = \left( \frac{45 + (-2)}{2}, \frac{0 + (-3)}{2} \right) = \left( \frac{43}{2}, -\frac{3}{2} \right) ) or (21.5, -1.5).
It is the midpoint of the class interval. I.e let b=the highest number in the class, a = the lowest number in the class. The midpoint is (a+ 1/2(b-a)).