25
2y-10y
No question has been posed.If you'd like to know what value of 'y' makes the statement true, you can find it as follows:10y - 4 = 24Add 4 to each side:10y = 28Divide each side by 10:y = 2.8
10y-4y = 6
10y = x ======
maximum value of 6y+10y
25
2y-10y
No question has been posed.If you'd like to know what value of 'y' makes the statement true, you can find it as follows:10y - 4 = 24Add 4 to each side:10y = 28Divide each side by 10:y = 2.8
10x-10y = 0
10y-4y = 6
10y = x ======
Treat it as a simultaneous equation question: -2x-10y = -12 3x+y = 4 Multiply all terms in the bottom equation by 10 in order to eliminate y: -2x-10y = -12 30x+10y = 40 Add both equations together: 28x+0 = 28 Divide both sides of the equation by 28 to find the value of x: x = 1 Substitute the value of x into the original equations to find the value of y: x = 1 and y = 1
10y=15y=1.5
8x - 10y = 27x - 5y = 13First, we need to eliminate one of the variables. For this, we would like to have them with the same coefficient but different sign. We can do this if we multiply by -2 the second equation.8x - 10y = 2-2(7x - 5y) = -2(13)8x - 10y = 2-14x +10y = -26Now, we can add both equations, and solve for x.(8x - 10y) + (-14x + 10y) = (2) + (-26)(8x - 14x) +(-10y + 10y) = (2 - 26)-6x = - 24-6x/-6 = - 24/-6x = 4Substitute 4 for x in the first equation:8x - 10y = 28(4) - 10y = 232 - 10y = 232 - 32 - 10y = 2 - 32-10y = -30-10y/-10 = -30/-10y = 3Thus, the solution of the system is (4, 3).Check:
You're there. 4x = 10y - 8.[so subtract 10y from both sides, 4x - 10y = -8]multiply b.s. by -1 , gives -4x +10y = 8
-6 - 10y = -10 Add 6 to both sides: -10y = -4 Divide both sides by -4: y = -4/-10 = 4/10 = 0.4 Check by putting the value back into the equation: -6 - (10 x 0.4) = -6 -4 = -10