In a 78 sided polygon, 1 unit each.
He shot 15 ducks and 12 rabbits. Algebraically, solve for one variable D = ducks (two feet) and R = Rabbits (four feet), and all have 1 head D + R = 27 2D + 4R = 78 --- 2D + 4R = 78 2D + 2R = 54 [ from 2(D + R) = 2(27) ] --- subtracting, 2R = 78 - 54 = 24 R = 12 D = 15 2 (15) + 4 (12) = 30 + 48 = 78 feet
-78
If the length is 12 feet and the width is 10.78 feet, then the perimeter is: length plus width times by two. (12 + 10.78) × 2 = 45.56 feet in total length.
78 * 78 = 6,084
heptacontaoctagon
You figure out 3-456=78+8xx79+m<K34 then divide that by 2
45agon 78agon 86agon. after like 12 sides you just add agon after the number.
In a 78 sided polygon, 1 unit each.
He shot 15 ducks and 12 rabbits. Algebraically, solve for one variable D = ducks (two feet) and R = Rabbits (four feet), and all have 1 head D + R = 27 2D + 4R = 78 --- 2D + 4R = 78 2D + 2R = 54 [ from 2(D + R) = 2(27) ] --- subtracting, 2R = 78 - 54 = 24 R = 12 D = 15 2 (15) + 4 (12) = 30 + 48 = 78 feet
-78
A faucet... Like a diamond which has many reflective surfaces.
a rhombus
An acute angle.
If the length is 12 feet and the width is 10.78 feet, then the perimeter is: length plus width times by two. (12 + 10.78) × 2 = 45.56 feet in total length.
Nitrogen-78%
no sorry he did not score 78 points in any game of his life