The given sequence consists of the cubes of the natural numbers: (1^3 = 1), (2^3 = 8), and (3^3 = 27). Following this pattern, the next number would be (4^3 = 64). Therefore, the missing number in the sequence is 64.
64
The sequence consists of the cubes of consecutive integers: (1^3 = 1), (2^3 = 8), (3^3 = 27), (4^3 = 64), (5^3 = 125), and (6^3 = 216). Therefore, the missing number in the sequence is 64.
The missing numbers in the sequence are 1, 8, 27, and 64, which correspond to the cubes of the integers 1, 2, 3, and 4, respectively. The next number in the sequence would be 125, which is the cube of 5 (5^3). To identify this, I recognized the pattern of perfect cubes in the sequence.
64 because it is basically cube each number in a row.
64
64
256
The sequence consists of the cubes of consecutive integers: (1^3 = 1), (2^3 = 8), (3^3 = 27), (4^3 = 64), (5^3 = 125), and (6^3 = 216). Therefore, the missing number in the sequence is 64.
64 should be in between 27 and 125.
64 because it is basically cube each number in a row.
64
what is the arthmetic sequence of 1 6 3 18 54 27 ? what is the missing terms ?
the answer has to be 1
64.The first number is 1 cubed, the second is 2 cubed, the third is 3 cubed, etc.
Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.
These are perfect cubes (of 1, 2 and 3) so the next two are 64 and 125
The sequence appears to be made up of the squares of consecutive integers: (1^2 = 1), (4^2 = 16), and (10^2 = 100). The missing number corresponds to (7^2), which is (49). Therefore, the missing number in the sequence is 49.