...... 42 59 78 ...
Just add consecutive prime numbers to each term i.e. 2 3 5 7 11 13 17 19 and so on
If you mean: 7 18 29 40 then the next term is 40+11 = 51
12, 8
47 4+7 = 11 7+11 = 18 11+18=29 18+29=47
It is obvious that 7 is added to get the next number from the previous one.
The next figure would be 21, followed by 11 & 10.
If you mean: 7 18 29 40 then the next term is 40+11 = 51
Oh, dude, the next term in that sequence is 25. You just add 7 each time, like it's no big deal. It's like basic math, man.
-2
31
The next term is 45 because the numbers are increasing by increments of 3 5 7 9 and then 11
12, 8
47 4+7 = 11 7+11 = 18 11+18=29 18+29=47
42 is the next number in this sequence. This number sequence is adding the next prime number to the last number. So 1 + 2 = 3. Then 3 + 3 = 6, 6 + 5 = 11, 11 + 7 = 18, 18 + 11 = 29. The next prime number after 11 is 13, so 29 + 13 = 42. The next numbers would be 59 (42+17), 78 (59+19), and 101 (78+23)
The given sequence is an arithmetic sequence with a common difference of 7 (18-11=7, 25-18=7, and so on). To find the nth term of an arithmetic sequence, you can use the formula: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the position of the term, and d is the common difference. In this case, the first term a_1 is 11 and the common difference d is 7. So, the nth term of this sequence is 11 + (n-1)7, which simplifies to 11 + 7n - 7, or 7n + 4.
18
It is obvious that 7 is added to get the next number from the previous one.
The nth term of the sequence is (n + 1)2 + 2.