It could be any number you like.
Given any fifth number it is easy to find a quartic polynomial (of degree 4) such that is passes through the given four points and the new one. Each choice of the fifth number will result in a different polynomial. So, since there are infinitely many choices for the fifth number, there are infinitely many position to value rules. In addition, there are non-polynomial functions as well.
The simplest answer is, perhaps, the cubic, Un = n3 - 9n2 + 32n - 10 for n = 1, 2, 3, ...
If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128
2n
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
37
The nth term is 7n-3 and so the next term will be 39
[ 6n + 8 ] is.
8 + (74 x 6) = 75th term. nth term = 8 + 6(n-1)
It is: 9n+5 and so the next term is 50
The nth term is (36 - 4n)
5+9n
If you meant: 2 12 22 32 then the nth term = 10n-8
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128
2n
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
37
The nth term is 7n-3 and so the next term will be 39