The simplest formula is:
t(n) = 2n + 5 for n = 1, 2, 3, ...
However, that is not the only formula; there are infinitely many polynomial formulae that can be found that give those five terms first, but for the 6th or further terms vary.
The nth term in the sequence -5, -7, -9, -11, -13 can be represented by the formula a_n = -2n - 3, where n is the position of the term in the sequence. In this case, the common difference between each term is -2, indicating a linear sequence. By substituting the position n into the formula, you can find the value of the nth term in the sequence.
(2n-1)(-1)n
Oh, dude, it's like a pattern party! So, to find the nth term for this sequence, you first need to figure out the pattern. Looks like each number is decreasing by 2. So, the nth term would be 13 - 2n. Easy peasy, right?
[ 25 - 6n ] is.
14+9n
It is: 2n+9
The nth term is: 2n+7 and so the next number will be 19
2n + 1
The nth term in the sequence -5, -7, -9, -11, -13 can be represented by the formula a_n = -2n - 3, where n is the position of the term in the sequence. In this case, the common difference between each term is -2, indicating a linear sequence. By substituting the position n into the formula, you can find the value of the nth term in the sequence.
It is 4n-13 and so the next number will be 11
The nth term is 2n+5 and so the next number is 17
nth term = 5 +8n
The nth term is: 5-6n
Un = 4n - 13.
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
The nth term is 3n+7 and so the next number will be 22
The nth term is: 3n+1 and so the next number will be 16