The simplest formula is:
t(n) = 2n + 5 for n = 1, 2, 3, ...
However, that is not the only formula; there are infinitely many polynomial formulae that can be found that give those five terms first, but for the 6th or further terms vary.
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The nth term in the sequence -5, -7, -9, -11, -13 can be represented by the formula a_n = -2n - 3, where n is the position of the term in the sequence. In this case, the common difference between each term is -2, indicating a linear sequence. By substituting the position n into the formula, you can find the value of the nth term in the sequence.
Oh, dude, it's like a pattern party! So, to find the nth term for this sequence, you first need to figure out the pattern. Looks like each number is decreasing by 2. So, the nth term would be 13 - 2n. Easy peasy, right?
(2n-1)(-1)n
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
[ 25 - 6n ] is.