37 - 9n
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
The given sequence is 12, 20, 28, 36, 44. To find the nth term, observe that the difference between consecutive terms is consistently 8. Therefore, we can express the nth term as ( a_n = 12 + 8(n - 1) ), which simplifies to ( a_n = 8n + 4 ). Thus, the nth term of the sequence is ( a_n = 8n + 4 ).
The 'n'th term is [ 13 + 5n ].
It is: 5n+3 and so the next term is 28
58
t(n) = 28 - 9n
nth term is n squared plus three
The nth term is (36 - 4n)
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
If the term number is n, then the nth term is 10(n-1) +8.
The nth term of the sequence is expressed by the formula 8n - 4.
28
If you mean: 8 28 48 and 68 then the nth term is 20n -12 and so the next number will be 88
28 - 8n
Well, darling, the nth term of 10, 16, 22, 28 is simply n multiplied by 6, then add 4. So if you're feeling adventurous and want to find the 10th term, just plug in n=10 and voila, you've got yourself 64. Keep it sassy and keep it real, honey!
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
The given sequence (7, 14, 21, 28, 35,....) is an arithmetic sequence where each term increases by 7. The nth term of the given sequence is 7n