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Well, it would depend what the sequence was...? If the sequence was 2,4,6,8,10,12,14,16,18,20, then the 9th term would be 18!
The 'n'th term is [ 13 + 5n ].
The sequence 3, 8, 13, 18, 23, 28 increases by 5 each time. This indicates a linear pattern. The nth term can be expressed as ( a_n = 3 + 5(n - 1) ), which simplifies to ( a_n = 5n - 2 ). Thus, the nth term of the sequence is ( 5n - 2 ).
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
Well, it would depend what the sequence was...? If the sequence was 2,4,6,8,10,12,14,16,18,20, then the 9th term would be 18!
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence is decreasing by 6 each time. Therefore, the nth term can be represented by the formula: 18 - 6(n-1), where n is the position of the term in the sequence.
The sequence 18, 27, 36, 45, 54 is an arithmetic sequence where each term increases by 9. To find the nth term, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term (18) and ( d ) is the common difference (9). Thus, the nth term is ( a_n = 18 + (n-1) \times 9 = 9n + 9 ).
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
The nth term of the sequence is (n + 1)2 + 2.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The sequence 3, 8, 13, 18, 23, 28 increases by 5 each time. This indicates a linear pattern. The nth term can be expressed as ( a_n = 3 + 5(n - 1) ), which simplifies to ( a_n = 5n - 2 ). Thus, the nth term of the sequence is ( 5n - 2 ).
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
The given sequence is an arithmetic sequence with a common difference of 7 (18-11=7, 25-18=7, and so on). To find the nth term of an arithmetic sequence, you can use the formula: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the position of the term, and d is the common difference. In this case, the first term a_1 is 11 and the common difference d is 7. So, the nth term of this sequence is 11 + (n-1)7, which simplifies to 11 + 7n - 7, or 7n + 4.