The sequence 8, 6, 4, 2, 0 is an arithmetic sequence with a common difference of -2. The first term (a) is 8, and the common difference (d) is -2. The nth term can be expressed using the formula: ( T_n = a + (n-1)d ). Thus, the nth term is given by ( T_n = 8 + (n-1)(-2) = 10 - 2n ).
n - 1
t(n) = n(n - 3)
The Nth term in the series is [ 2N ] .
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
They are: nth term = 6n-4 and the 14th term is 80
n - 1
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
t(n) = n(n - 3)
The nth term is (2n - 12).
(n2+n+2) / 2, starting with n=0.
The Nth term in the series is [ 2N ] .
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
If you mean: 3, 4, 5, 6 and 7 then nth term = n+2
They are: nth term = 6n-4 and the 14th term is 80
11
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
16 - 4nor4 (4 - n)