To find the nth term of the sequence 9, 12, 17, 24, 33, we first look at the differences between consecutive terms: 3, 5, 7, and 9. These differences themselves increase by 2, indicating a quadratic relationship. We can derive the nth term formula as ( a_n = n^2 + 8n + 1 ). Thus, the nth term of the sequence can be expressed as ( a_n = n^2 + 8n + 1 ).
If you mean: 6 12 18 24 then the nth term is 6n
To find the nth term of the sequence 9, 12, 17, 24, 33, 44, we first observe the differences between consecutive terms: 3, 5, 7, 9, 11. These differences form an arithmetic sequence with a common difference of 2. This suggests that the nth term can be expressed as a quadratic function. By deriving the formula, the nth term is given by ( a_n = n^2 + 8n - 1 ).
Well, darling, the nth term for the sequence 18, 12, 6, 0, -6 is -6n + 24. So, if you plug in n = 1, you get 18; n = 2 gives you 12, and so on. Just a little math magic for you to enjoy!
The sequence 3, 10, 17, 24 increases by 7 each time. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Here, ( a_1 = 3 ) and ( d = 7 ), so the nth term is ( a_n = 3 + (n-1) \times 7 = 7n - 4 ).
-4n + 24 #1 ; -4(1) +24 = 20 #2 ; -4(2) + 24 = 16 #3 ; =4(3) + 24 = 12
44
If you mean: 6 12 18 24 then the nth term is 6n
To find the nth term of the sequence 9, 12, 17, 24, 33, 44, we first observe the differences between consecutive terms: 3, 5, 7, 9, 11. These differences form an arithmetic sequence with a common difference of 2. This suggests that the nth term can be expressed as a quadratic function. By deriving the formula, the nth term is given by ( a_n = n^2 + 8n - 1 ).
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
7n - 4
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
Well, darling, the nth term for the sequence 18, 12, 6, 0, -6 is -6n + 24. So, if you plug in n = 1, you get 18; n = 2 gives you 12, and so on. Just a little math magic for you to enjoy!
For {12, 15, 18} each term is the previous term plus 3; a general formula for the nth term is given by t(n) = 3n + 9. For {12, 24, 36} each term is the previous term plus 12; a general formula for the nth term is given by t(n) = 12n.
The nth term is 7n-4 and so the next number in the sequence is 31
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The nth term is (36 - 4n)