To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
tn = 34 - 9n where n = 1,2,3,...
[ 25 - 6n ] is.
The sequence 11, 18, 25, 32, 39 has a common difference of 7. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 = 11 ) and ( d = 7 ). Thus, the nth term is given by ( a_n = 11 + (n-1) \times 7 = 7n + 4 ).
T(n) = 25 - 6n
20-9x=n
The nth term is 9n-2
The nth term = 9n-2
tn = 34 - 9n where n = 1,2,3,...
The nth term is: 5-6n
The nth term is 6n+1 and so the next term will be 31
The nth term is 3n+7 and so the next number will be 22
The nth term is: 3n+1 and so the next number will be 16
25
75988 to the 7th
[ 25 - 6n ] is.
The sequence 11, 18, 25, 32, 39 has a common difference of 7. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 = 11 ) and ( d = 7 ). Thus, the nth term is given by ( a_n = 11 + (n-1) \times 7 = 7n + 4 ).
2n+1