tn = 34 - 9n where n = 1,2,3,...
To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
It is: 25-7n
7n - 3
tn = n2
Un = 25 - 7n
The nth term is 9n-2
To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
n2
7n - 3
It is: 25-7n
The nth term = 9n-2
tn = n2
Un = 25 - 7n
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
3n^2 - n + 1
The nth term is 7n-3 and so the next term will be 39
To find the nth term of the sequence 3, 11, 25, 45, we first look for a pattern in the differences between the terms. The first differences are 8, 14, and 20, and the second differences are 6, 6, indicating that the sequence is quadratic. We can express the nth term as ( a_n = An^2 + Bn + C ). Solving for A, B, and C using the given terms, we find the nth term is ( a_n = 3n^2 - 3n + 3 ).