It is only because we count in tens - and 5 10 and 2 are factors.
4194304 = 222
The equivalent is 7s+2s = 9s
The last number consists of one 3 followed by one 1 followed by two 2s followed by two 1s Stringing all these numbers together gives 13112221
9r2-4s2/9r+6sIt looks like you can factors the numerator(3r + 2s)(3r - 2s) [This is the factored form of 9r2-4s2]Put this back into the equation(3r+2s)(3r-2s)/9r+6sYou can also factor the denominator3(3r+2s)Put this back into the equation(3r+2s)(3r-2s)/3(3r+2s)You can cancel out the 3r+2s on top and bottom because they are the same they equal 1. Therefore your final answer is3r-2s over 3You could go further and say this is...r-(2/3)seither one is correct
2, 4, 6, 8, 12, 14, 16
The maximum number of electrons that can go into the 2s sublevel is 2.
2, 4, 6 3, 6 The LCM of 2 and 3 is 6.
2s - 12 + 2s = 4s - 124s - 12 = 4s - 124s = 4ss = s==========this is an identity and any number can be s
unknown
21- only true legends know
It is a mixed number.
The 2s sublevel can hold a maximum of 2 electrons.
It is only because we count in tens - and 5 10 and 2 are factors.
The difference between the number of 2s and the number of 4s in a sum.
2121
The first quantum number of a 2s electron in phosphorus is the principal quantum number, which specifies the energy level of the electron shell. For a 2s electron, the principal quantum number is 2.