Zero.
There are two, 0 and 1.
Of course you can. But any number multiplied by zero always equals to 0.
There is no number related to the original (as implied by "its what") that will do.
The number that, when multiplied by itself, equals the original number is 1. This is because (1 \times 1 = 1). Additionally, the number 0 also satisfies this condition, as (0 \times 0 = 0). Hence, both 0 and 1 are numbers that meet this criterion.
2 multiplied by 0 equals 0. In multiplication, any number multiplied by zero results in zero. Therefore, 2x0 = 0.
Let the number be 'm' & 'n'. Hence mn = 54 m + n = 0 It follows m = 0 - n Substitute 0 - n + n = 0 n - n = 0 Hence there are no two numbers that satisfy this system.
There are two, 0 and 1.
7 • 0 = 0. Any number multiplied by 0 is 0.
Of course you can. But any number multiplied by zero always equals to 0.
0. Any number multiplied by zero equals zero.
There is no number related to the original (as implied by "its what") that will do.
The number that, when multiplied by itself, equals the original number is 1. This is because (1 \times 1 = 1). Additionally, the number 0 also satisfies this condition, as (0 \times 0 = 0). Hence, both 0 and 1 are numbers that meet this criterion.
2 multiplied by 0 equals 0. In multiplication, any number multiplied by zero results in zero. Therefore, 2x0 = 0.
0. Anything multiplied by 0 equals 0.
0. Any number multiplied by zero equals zero
Any number multiplied by zero is always zero. Therefore, 5 x 0 equals 0.
If 5n = 0 then n = 0, and any number of n's = 0.6n = 0