There is a formula for "the difference of squares." (x + 7)(x - 7) = 0 x = 7, -7
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}
Factor the original equation to get (x-7)(x+2)=0, so x=7 or x=-2
x = 12
If: x = 2/3 and x = 5/7 Then: (3x-2)(7x-5) = 0 Equation: 21x2-29x+10 = 0
x2 + 7x = 0 => x*(x + 7) = 0 => x = 0 or x + 7 = 0 so that x = 0 or x = -7
x^2 - 7x = 0 x(x - 7) = 0 x = 0 or x - 7 = 0 x = 0 or x = 7
There is no answer to this (for any value of x) That's because x-x = 0 So x-x-7 is always -7, and never 0
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5x2 + 12x + 7 = 0 This equation can be factored : (5x + 7) (x + 1) = 0 The equation equals zero when either 5x + 7 = 0 or x + 1 = 0 When 5x + 7 = 0 then 5x = -7 : x = -7/5 or -1.4 When x + 1 = 0 then x = -1 The solutions or roots of this equation are x = -7/5 and x = -1
2x2 + 7x = 0 => x(2x+7)=0 so x = 0 or 2x+7 = 0 ie x = 0 or x = -7/2
There is a formula for "the difference of squares." (x + 7)(x - 7) = 0 x = 7, -7
X * (X - 7) = 0 = X² - 7X D (discriminant) = (-7)² - 4 * (1 * 0) = 49 X1 = (7 - 7)/2 = 0 X2 = (7+ 7)/2 = 7
63
The answer to the question, as stated, is that it is a quadratic equation in one unknown, x.The solution to the equation is as follows:x2 - 6x - 7 = 0 ie x2 - 7x + x - 7 = 0 or x(x-7) +1(x-7) = 0(x+1)(x-7) = 0 so that x+1 = 0 or x-7 = 0 and so x = -1 or x = 7.
y=x+7 x - intercept set y to 0 0=x+7 -7 -7 -7=x (-7,0) y - intercept set x to 0 y=0+7 y=7 (0,7) (-7,0) , (0,7)