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What is the number of different ways that 2 out of 12 students can volunteer to organize a class party?
The first student can be any one of 12. For each of those . . .
The second student can be any one of 11.
So there are (12 x 11) = 132 different ways that a pair can be formed from the 12 students.
But for every pair, there's another one that's exactly identical to it . . . Betsy and Joann is exactly
the same pair as Joann and Betsy.
So the number of different pairs is half of the number of ways they can be picked, (132/2) = 66 different pairs.
What else can I help you with?
How many different committees can be formed from 6 teachers and 49 students if the committee consists of 4 teachers and 4 students?
To determine the number of different committees that can be formed with 4 teachers from 6 and 4 students from 49, we use combinations. The number of ways to choose 4 teachers from 6 is given by ( \binom{6}{4} ), and the number of ways to choose 4 students from 49 is ( \binom{49}{4} ). Thus, the total number of different committees is ( \binom{6}{4} \times \binom{49}{4} ). Calculating this gives ( 15 \times 194580 = 2918700 ) different committees.
How many different groups of students can be formed from 16?
The number of different groups of students that can be formed from 16 students depends on the size of the groups being formed. If you are looking for all possible combinations of groups of any size (from 1 to 16), you can use the formula for combinations. The total number of combinations would be (2^{16} - 1) (subtracting 1 to exclude the empty group), which equals 65,535 different groups. If you specify a particular group size, the calculation would be different.
What is the student enrollment (in the total number of students)?
“What is the student enrollment (in the total number of students)?”
How many ways can six students be arrange in a lunch line?
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
On a math test 12 students earned an a this number is exactly 25 percent of the total number of students in the class how many students are in the class?
48
How do you organize a quiz competitions for students in the church?
There are a number of ways to organize quiz competitions for students in the church. The best way is to compile questions for three different levels, each level getting harder then the previous. Each student should be asked a question for the first round, if they answer it wrong they are eliminated, if they answer it correctly they can go on to the next round.
How do you solve correct average given number of students and the different of scores?
You add all the scores, then divide by the number of students.
Can 100 students arrange themselves in 7 different teams if there are to be the same number of students on each side?
No.
What is the phone number of the Benicia Volunteer Firemen in Benicia California?
The phone number of the Benicia Volunteer Firemen is: 707-745-1688.
What is the phone number of the Brookhaven Volunteer Fire in Ridge New York?
The phone number of the Brookhaven Volunteer Fire is: 631-924-8114.
What is the phone number of the Kingston Volunteer Firemans in Kingston New York?
The phone number of the Kingston Volunteer Firemans is: 845-331-0866.
What is the phone number of the Cranston Volunteer Firefighter in Cranston Rhode Island?
The phone number of the Cranston Volunteer Firefighter is: 401-828-4333.
Can you do volunteer work without a social security number?
Yes, to volunteer for something mean you do it for free so no social security number will be needed or asked for.
What is the phone number of the 7Th Iowa Volunteer Cavala in Minburn Iowa?
The phone number of the 7Th Iowa Volunteer Cavala is: 515-993-5218.
Is number of students continuous or discrete?
The number of students is discrete. There is no number of students between 4 and 5.
How many different committees can be formed from 6 teachers and 49 students if the committee consists of 4 teachers and 4 students?
To determine the number of different committees that can be formed with 4 teachers from 6 and 4 students from 49, we use combinations. The number of ways to choose 4 teachers from 6 is given by ( \binom{6}{4} ), and the number of ways to choose 4 students from 49 is ( \binom{49}{4} ). Thus, the total number of different committees is ( \binom{6}{4} \times \binom{49}{4} ). Calculating this gives ( 15 \times 194580 = 2918700 ) different committees.
Is the number of students on the y- axis?
That depends on if the variable "number of students" is dependent on something else. For example, if the number of students is dependent on the time of year, then it is charted along the y-axis. If the number of students is independent, and the school's yearly expenses are dependent on the number of students, than the number of students should be tracked by the x-axis.
