A 4-input decoder can produce (2^n) outputs, where (n) is the number of inputs. For a 4-input decoder, (n = 4), so the number of possible outputs is (2^4 = 16). Therefore, a 4-input decoder can generate 16 distinct output lines based on the 4 input combinations.
To create a 6 to 64 decoder using four 4 to 16 decoders and one 2 to 4 decoder, first, separate the 6 input bits into two groups: the upper 2 bits (let's call them A5 and A4) and the lower 4 bits (A3 to A0). Use the 2 to 4 decoder to decode the upper 2 bits, which will select one of the four 4 to 16 decoders. Then, connect the lower 4 bits to all four 4 to 16 decoders. The selected 4 to 16 decoder will activate one of its 16 outputs based on the lower 4 bits, resulting in a total of 64 outputs from the combination of the decoders.
In a decoder circuit, only one output is activated at a time because it is designed to represent a unique binary input combination. The logic gates within the decoder ensure that each specific input corresponds to a single output line being high (active), while all other outputs remain low (inactive). This one-hot encoding scheme prevents ambiguity and ensures clear and distinct representation of the input state, which is crucial for accurate digital processing and control.
The salary problem has 2 outputs for each input value.
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A 4-input decoder can produce (2^n) outputs, where (n) is the number of inputs. For a 4-input decoder, (n = 4), so the number of possible outputs is (2^4 = 16). Therefore, a 4-input decoder can generate 16 distinct output lines based on the 4 input combinations.
The DSTV decoder connects to a Satellite Dish on the top of your house. That dish receives a digital satellite television (DSTV) signal. Your decoder then decodes this signal and outputs it into your TV.
The 74138 is a 3 to 8 decoder. When enabled, one of the 8 outputs is low, based on the binary value of the 3 inputs.
To create a 6 to 64 decoder using four 4 to 16 decoders and one 2 to 4 decoder, first, separate the 6 input bits into two groups: the upper 2 bits (let's call them A5 and A4) and the lower 4 bits (A3 to A0). Use the 2 to 4 decoder to decode the upper 2 bits, which will select one of the four 4 to 16 decoders. Then, connect the lower 4 bits to all four 4 to 16 decoders. The selected 4 to 16 decoder will activate one of its 16 outputs based on the lower 4 bits, resulting in a total of 64 outputs from the combination of the decoders.
A printer is a machine that accepts graphic outputs from the computer and transfers the information into the paper. This can vary in sizes, sophistication, cost and speed.
It turned out to be very easy))) But I was thinking for a while to solve the problem... )))Ok. Lets say we have inputs S3..S0. Let S3 and S2 go to inputs of each of FOUR of decoders; and S1 with S0 go to the inputs of the FIFTH decoder. The four outputs of the FIFTH decoder go to enable lines of the four decoders. Voila! It might be confusing, but just draw the whole thing and you'll see. Now you just need to enable the fifth decoder... HA-HA!
connect S1 and S0 to a 2x4 active high decoder then connect each output of the decoder with the enable of each three-state buffer. Each of with has an input of D0,D1,D2,D3 respectively. Connect the outputs of each with an OR gate (since only one can be active at a time, whichever's active will be the output).
any body can help on this ?
The present astromax has lot of problems ( teething) so improved version expected next year 2009? Capable of HD but with component outputs. Wait and see first to believe.
Start with 3/8 decoders and connect only the four outputs of each other that have the first bit 1 loads.
The two different output levels on a 3-way signal splitter are due to signal loss that occurs when the input signal is divided among multiple outputs. The splitter is designed to evenly distribute the signal across all outputs, but some loss is unavoidable. The outputs may have slightly different signal levels depending on the design and quality of the splitter.