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What is the number of inputs and outputs of a decoder that accepts 128 different input combinations?
A decoder that accepts 128 different input combinations requires 7 input lines, as (2^7 = 128). The number of output lines corresponds to the number of unique output combinations, which is also 128, since each input combination produces a distinct output. Therefore, the decoder will have 7 inputs and 128 outputs.
How many outputs are possible for 4 input decoder?
A 4-input decoder can produce (2^n) outputs, where (n) is the number of inputs. For a 4-input decoder, (n = 4), so the number of possible outputs is (2^4 = 16). Therefore, a 4-input decoder can generate 16 distinct output lines based on the 4 input combinations.
How many input lines for n-2n decoder?
An n-to-2^n decoder has n input lines. Each combination of the n input lines corresponds to one of the 2^n output lines being activated. Thus, for a decoder to function correctly, it requires exactly n input lines to decode the binary input into a specific output line.
How many cross points would be required if there were no distinction between input and output lines?
n: inputs n ( n - 1 ) / 2
How many data line does a 4 to 1 multiplexer have?
A 4 to 1 multiplexer has four data lines, typically labeled as D0, D1, D2, and D3. It uses two select lines to choose which of the four data inputs is routed to the output. Therefore, it can select one of four different data inputs based on the values of the select lines.
N-2n decoder input and output lines?
An N-2N decoder is a digital circuit that converts N input lines into 2^N output lines. For each unique combination of the input lines, one specific output line is activated while all others remain inactive. For instance, if there are 3 input lines (N=3), the decoder will produce 2^3 = 8 output lines, allowing it to represent all combinations of the 3 inputs. This type of decoder is commonly used in memory address decoding and data routing applications.
What decoder chip converts 7 lines to 3 lines?
Decoder is a circuit which have n inputs and 2^n outputs.I think you want to say encoder which have 2^n input and n output lines. So your required chip is 8(2^3)X3 encoder which does not exist.
Number of control lines for a 16 output decoder?
4
How does a memory decoder 74Ls138 function?
The 74LS138 is a 3-to-8 line decoder that takes 3 input binary signals and activates one of eight output lines based on those inputs. It features three select inputs (A0, A1, A2) that determine which output (Y0 to Y7) will be low (active), while all other outputs remain high (inactive). The decoder also has enable inputs to control its operation; if the enables are not activated, none of the outputs will be activated. This device is commonly used in memory address decoding and data routing applications.
How many outputs are possible for 4 input decoder?
A 4-input decoder can produce (2^n) outputs, where (n) is the number of inputs. For a 4-input decoder, (n = 4), so the number of possible outputs is (2^4 = 16). Therefore, a 4-input decoder can generate 16 distinct output lines based on the 4 input combinations.
Explain Implementation of full adder with a decoder?
A full adder can be implemented using a decoder by utilizing a 3-to-8 line decoder to decode the three input bits: A, B, and Carry-in (Cin). The decoder generates eight output lines corresponding to all possible combinations of the three inputs. The outputs of the decoder can then be combined with logic gates to derive the Sum and Carry-out outputs of the full adder. Specifically, the Sum output can be generated by ORing the appropriate outputs of the decoder, and the Carry-out can be derived from a combination of specific outputs as well.
What is difference between decoder and demultiplexer?
mohammed.eng.2005@gmail.com ---- The differences between these two circuits is subtle, as far as I can tell. A demux simply selects an output line, nothing more. It's a glorified switch. A decoder takes n inputs, and uses those inputs to determine which of the 2^n output lines is high. This is the difference, I think. A decoder is designed to simply keep one line high. A demux is designed to set one output equal to the input (whether it be high, low, or a changing signal).
How many input lines for n-2n decoder?
An n-to-2^n decoder has n input lines. Each combination of the n input lines corresponds to one of the 2^n output lines being activated. Thus, for a decoder to function correctly, it requires exactly n input lines to decode the binary input into a specific output line.
What is tb for decoder 4 to 16?
In the context of digital electronics, "tb" typically refers to the timing behavior or timing diagram for a decoder, specifically a 4-to-16 line decoder. A 4-to-16 decoder takes 4 input binary signals and decodes them into one of 16 output lines, with only one output being active (logic high) at any time corresponding to the binary value of the inputs. The timing diagram would illustrate the relationship between the input signals and the active output over time, showing the propagation delay as the input changes and the output stabilizes.
I wanted the theory for implementation of full adder using 3 to 8 decoder and 4 input nand gates?
A full adder is a logic circuit that take two inputs and a carry input, and produces an output and a carry ouput. It is one stage in a multi-bit adder. The truth table is: ABC RC D000 00 0001 10 1010 10 2011 01 3100 10 4101 01 5110 01 6111 11 7The columns are A, B, Carry Input, Result, Carry Output, and Decoder Output You can use a 3 to 8 decoder to generate these 8 lines. Look at the R and C outputs, and note that there are 4 combinations of inputs thet generate a 1 or a 0. For each of Result and Carry Ouput, connect the decoder output representing the 0 state to those four lines. (Result = 0, 3, 5, 6. Carry Output = 0, 1, 2, 4) What you are doing logically is or'ing the lines to produce the 1's. Since you have nands instead or ors, treat the nands as nors and pick the opposite inputs.
How can you design 4-to-16 decoder with five 2-to-4 decoder?
It turned out to be very easy))) But I was thinking for a while to solve the problem... )))Ok. Lets say we have inputs S3..S0. Let S3 and S2 go to inputs of each of FOUR of decoders; and S1 with S0 go to the inputs of the FIFTH decoder. The four outputs of the FIFTH decoder go to enable lines of the four decoders. Voila! It might be confusing, but just draw the whole thing and you'll see. Now you just need to enable the fifth decoder... HA-HA!
Why are inverters on the output of the 74LS138 CHIP?
In high-performance memory systems these decoders can be used to minimize the effects of system decoding. When used with high-speed memories, the delay times of these decoders are usually less than the typical access time of the memory. This means that the effective system delay introduced by the decoder is negligible. The DM74LS138 decodes one-of-eight lines, based upon the conditions at the three binary select inputs and the three enable inputs. Two active-low and one active-high enable inputs reduce the need for external gates or inverters when expanding. A 24-line decoder can be implemented with no external inverters, and a 32-line decoder requires only one inverter.
