To do this manually, you can simply read through the number, keeping a manual tally in your head. If you are looking for an algorithm to do it for you, here is one method that would work in C, where "number" is the value being tested and "digit" is the digit we're counting: ... int whole = (int)number; number -= whole; tally = 0; while(whole != 0){ if(whole % 10 digit) tally++; number -= (int)number; } printf("We counted %i digits occurrences of the digit %i\n", tally, digit); ...
#include<iostream.h> #include<conio.h> void main(){ int Number[10]; cout<<"Enter ten numbers"; for (int i=0;i<10;i++) cin>>Number[i]; int Big=0; for(int j=0;j<10;j++){ if (Big<Number[i]) Big=Number[i]; } cout<<"gretest Number:"<<Big; getch(); }
int factorial(int n) { int i; int f=1; for(i=2;i<=n;++i) f*=i; return f; }
public class FindLeastAndGreatest { public static void main(String[] args) { // number can't be equal with each other int a = 7; int b = 7; int c = 6; System.out.println(least(a,b,c)); System.out.println(greatest(a,b,c)); } public static int least(int a, int b, int c) { int least = 0; if(a < b && a < c) { least = a; } else if(b < a && b < c) { least = b; } else { least = c;} return least; } public static int greatest(int a, int b, int c) { int greatest = 0; if(a > b && a > c) { greatest = a; } else if(b > a && b > c) { greatest = b; } else { greatest = c;} return greatest; } }
/*program to find the factorial of a given number*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,c; printf("\n enter the number for which you want to find the factorial"); scanf("%d",&n); c=fact(n); printf("\n the factorial of the number %d is %d",n,fact); getch(); } int fact(int n) { int k; if(n==0) return(1); else k=n*fact(n-1); return(k); }
I just read the best magazines in the world. I will read these magazines tomorrow.
There are a number of magazines that specialize in automotive issues. For the best information, one can select magazines such as Motor Trend, Road and Track, and Car and Driver, which are by far the most popular such magazines.
same way i read this question
"Leer revistas y novelas" means "to read magazines and novels" in English.
yes she can read if she a singer she have to know how to read the lyrics magazines
int main() { int numbers[10]; int j; for (j=0; j<10; j++) { scanf("%d", &number[j]); } printf( "%d %d\n", number[0], number[1]); printf( "%d %d\n", number[2], number[3]); return 0; }
Math.h doesn't containing the round function. Use the following, int round(double number) { return (number >= 0) ? (int)(number + 0.5) : (int)(number - 0.5); }
To do this manually, you can simply read through the number, keeping a manual tally in your head. If you are looking for an algorithm to do it for you, here is one method that would work in C, where "number" is the value being tested and "digit" is the digit we're counting: ... int whole = (int)number; number -= whole; tally = 0; while(whole != 0){ if(whole % 10 digit) tally++; number -= (int)number; } printf("We counted %i digits occurrences of the digit %i\n", tally, digit); ...
Times online provides magazines. It alowes people to read the latest magazine online if they have a subscription. It also alowes people to read the magazines they didn't get to read prevously.
newspaper, internet, television and magazines
coz they find them interesting
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