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What is range of 8-bit signed integer?
-128 to 127, in two's-complement.
Describe the range of numbers that can be represented by a 8 bit number using two complement?
-128 to 127
Twos complement of a given 3 or more bit binary number of non-zero magnitude is the same the original number if all bits except the?
ANSWER: MSB IS 1 In the 2's complement representation, the 2's complement of a binary number is obtained by first finding the one's complement (flipping all the bits), and then adding 1 to the result. This representation is commonly used to represent signed integers in binary form. Now, if all bits except the sign bit are the same, taking the 2's complement of the binary number will result in the negative of the original number. The sign bit (the leftmost bit) is flipped, changing the sign of the entire number. For example, let's take the 4-bit binary number 1101 The 2's complement would be obtained as follows: Find the one's complement: 0010 Add 1 to the one's complement: 0011
What is the numeric range of 16-bit unsigned binary value?
0..65535 Note: check me using your calc.exe: 65535 = 2^16-1
What is the decimal equalent to hexadecimal(fd) h?
As hexadecimal uses the letters a-f to continue the digits after 0-9, a = 10, b = 11, ... f = 15 for the single digit that can be represented in each place value column, each of which is sixteen (16) times bigger than the one on its right. → 0xfd = f x 16 + d = 15 x 16 + 13 = 253. In signed numbers, the top bit is used as a sign indicator and if set represents a negative number; thus a byte of 8 bits can be used to represent a number in the range -128 to +127. In this case the bit pattern represented by the hex 0xfd would represent -3. To work out the number, invert all the bits (forming the ones complement) and add 1 (forming the twos complement): 0xfd = 11111101 in binary → 0000010 = 0x02 in hex (ones complement) → 0xfd = -(0x02 + 1 ) = -(0x03) = -3
