Off the top of my head, 1001 is the answer. Check it out and see . . .
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1001 is not prime. 7 X 143 equals 1001.
There is 11, which is prime and which has 2 digits.
No, 11 is the only palindromic prime with an even number of digits.
It is 2 which also is the only even prime number
The only two digit numbers whose digits add up to 17 are 89 and 98. Since 98 is an even number, 89 is prime.
It is composite, as are all whole numbers whose last digits are even.
The two-digit primes less than 50 are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, and 47. For each prime on this list whose tens digit is odd, check whether or not the number formed when the digits are reversed is also prime. (Note that if the tens digit is even, then the ``reversed'' number is even and hence not prime.) The palindromic primes less than 50 are 11, 13, 17, 31, and 37, whose sum is 109.
No, 11 is the only palindromic prime with an even number of digits.
11
It is 2 which also is the only even prime number
The only two digit numbers whose digits add up to 17 are 89 and 98. Since 98 is an even number, 89 is prime.
2 is the only even prime any number ending in 2 is divisible by 2 and not prime any even number greater than 2 is divisible by 2 and not prime unless i misunderstood there can be no answer
It is composite, as are all whole numbers whose last digits are even.
The two-digit primes less than 50 are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, and 47. For each prime on this list whose tens digit is odd, check whether or not the number formed when the digits are reversed is also prime. (Note that if the tens digit is even, then the ``reversed'' number is even and hence not prime.) The palindromic primes less than 50 are 11, 13, 17, 31, and 37, whose sum is 109.
To be an even number then the final digit = 2. The largest single prime digit is 7 (as both 8 and 9 are composite). The greatest even number fulfilling the conditions is 77777772.
If you multiply two prime numbers, the product (result) will be a composite number, not a prime number. A prime number has exactly two factors, 1 and itself. The product of two prime numbers will have those two numbers as factors, as well. The sum of two prime numbers might be prime if one of those two numbers is 2, the only even prime number, but otherwise it will not be a prime because two odd numbers will have an even sum, which means it is divisible by 2. Examples: 2 + 3 = 5 (prime) 3 + 7 = 10 (not prime) 13 + 17 = 30 (not prime) If you multiply two prime numbers, the sum of the digits of the product might or might not be prime. Examples: 2 x 7 = 14, sum of digits is 5 (prime) 2 x 11 = 22, sum of digits is 4 (not prime) 3 x 5 = 15, sum of digits is 6 (not prime) 3 x 7 = 21, sum of digits is 3 (prime) 5 x 7 = 35, sum of digits is 8 (prime)
60006 in order to make it even the back number also has to be even
The number is 222.
There are more 12-digit palindromic numbers than 11-digit palindromic numbers. This is because the number of possible 12-digit palindromic numbers is greater than the number of possible 11-digit palindromic numbers. In general, the number of palindromic numbers of length n is 9 * 10^((n-1)/2), so for 11-digit palindromic numbers, there are 9 * 10^5 = 900,000 possibilities, while for 12-digit palindromic numbers, there are 9 * 10^6 = 9,000,000 possibilities.