The lines intersect at (3, 5)
- 2(3X - 8Y = - 18)3(2X + 5Y = 19)- 6X + 16Y = 366X + 15Y = 57----------------------------add31Y = 93Y = 3========now, find X; second equation will do2X + 5(3) = 192X + 15 = 192X = 4X = 2==========both check and are consistent(2, 3)-----------------ordered pair
x = 2 and y =1 so the lines intersect at (2, 1)
-8-5y = 12-9y 9y-5y - 12+8 4y = 20 y = 5
Y=-1
The solutions are: x = -2 and y = 4
(10, 2)
The lines intersect at (3, 5)
The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.
- 2(3X - 8Y = - 18)3(2X + 5Y = 19)- 6X + 16Y = 366X + 15Y = 57----------------------------add31Y = 93Y = 3========now, find X; second equation will do2X + 5(3) = 192X + 15 = 192X = 4X = 2==========both check and are consistent(2, 3)-----------------ordered pair
y=(-1) x=(2)
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
x = 2 and y =1 so the lines intersect at (2, 1)
2x + 5y = 16 + (-5x) - 2y = 2 That gives 2x + 5y = 2 . . . . . . . . . . (I) and -5x - 2y = - 14 or 5x + 2y = 14 . . . . (II) (I)*5: 10x + 25y = 10 (II)*2: 10x + 4y = 28 Subtracting the second from the first, 21y = -18 so y = -18/21 = -6/7 and then by (I) x = 1 - 5y/2 = 1 - 5/2*(-6/7) = 1 + 15/7 = 22/7 So the ordered pair is (22/7, -6/7)
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation.
-8-5y = 12-9y 9y-5y - 12+8 4y = 20 y = 5
5(y-4)