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Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation.

Q: Which ordered pair is on the graph of the equation 2x 5y 4?

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x = 12 y = 2 (12,2) satifies the equation

You can set variable "x" to any value, and then calculate the corresponding value for "y" - that will give you an ordered pair.

You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.

The ordered pair is (1, 3).

A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.

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The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.

5x27

2x - 5y8 is an expression. It is not an equation and so cannot have a solution.

2x - 2y8 is an expression. It is not an equation and so cannot have a solution.

x = 12 y = 2 (12,2) satifies the equation

There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.

2

The equation 2x - 3y = 6 is a linear equation and a linear equation is always has a straight line as a graph

There are an infinite number of solutions to this equation, some of which are (9,0), (12,2), (15,4), (18,6), (21,8)

You can set variable "x" to any value, and then calculate the corresponding value for "y" - that will give you an ordered pair.

2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)

Yes. Yes, it could. So could (0, -1) or (2, 3). Or, if you want, (x, 2x-1).