Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation.
x = 12 y = 2 (12,2) satifies the equation
You can set variable "x" to any value, and then calculate the corresponding value for "y" - that will give you an ordered pair.
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
The ordered pair is (1, 3).
A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.
5x27
2x - 5y8 is an expression. It is not an equation and so cannot have a solution.
2x - 2y8 is an expression. It is not an equation and so cannot have a solution.
x = 12 y = 2 (12,2) satifies the equation
There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.
2
There are an infinite number of solutions to this equation, some of which are (9,0), (12,2), (15,4), (18,6), (21,8)
The equation 2x - 3y = 6 is a linear equation and a linear equation is always has a straight line as a graph
You can set variable "x" to any value, and then calculate the corresponding value for "y" - that will give you an ordered pair.
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
Yes. Yes, it could. So could (0, -1) or (2, 3). Or, if you want, (x, 2x-1).