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The equation you provided seems to be missing an equal sign. Assuming you meant ( y = 3x + 1 ), the input-output table can be created by substituting different values for ( x ). For example: If ( x = 0 ), then ( y = 3(0) + 1 = 1 ). If ( x = 1 ), then ( y = 3(1) + 1 = 4 ). If ( x = 2 ), then ( y = 3(2) + 1 = 7 ). The table would look like this: | ( x ) | ( y ) | |---------|---------| | 0 | 1 | | 1 | 4 | | 2 | 7 |
Each equation will have it's own input/ output table, where you put in a value for y and get a value for x or put in a value for k and get a value for y For example : y = -7 + 3x Y | X _|____ 0 | 7/3. 1 | 8/3. -7 | 0. (unfortunatly the WikiAnswers cannot be formatted as I'd like but the above should be a table with Y valyues on the left and X values on the right) Now do the same for the other equation: y = 5x - 13 Y | X _|____ 0 | 13/5. 1 | 12/5. -13 | 0.
We want to know for what x will Fy(x) = 30. Let's look at what Fy does: There are 3 feet in a yard, so to get from yards to feet, Fy takes the input x, and multiplies it by 3: x (yards) * 3 (feet/yard) = 3*x feet Thus we want to solve 3x = 30 Divide both sides by 3: x = 10
-3x+4y doesn't have a maximum value because you can plug in anything for x and anything for y. In fact, if you keep x=0 and you plug in larger and larger numbers for y, you get a larger and larger output--it's unbounded.
To enter the equations ( x - y^4 ) and ( 3x - 5y^2 ) into a calculator for graphing or solving, you typically need to solve for ( y ) in terms of ( x ). For ( x - y^4 = 0 ), rearrange to ( y^4 = x ), giving ( y = x^{1/4} ). For ( 3x - 5y^2 = 0 ), rearrange to ( y^2 = \frac{3x}{5} ), leading to ( y = \sqrt{\frac{3x}{5}} ). Input these as ( y = x^{1/4} ) and ( y = \sqrt{\frac{3x}{5}} ) respectively.
It is 4.
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the output variable is called the dependent variable. For example the function y = f(x) = 3x here x is independent and y is dependent; y changes when you change x
It would be a straight line with gradient 3, which would intercept the y axis at the point (0,2).
Each equation will have it's own input/ output table, where you put in a value for y and get a value for x or put in a value for k and get a value for y For example : y = -7 + 3x Y | X _|____ 0 | 7/3. 1 | 8/3. -7 | 0. (unfortunatly the WikiAnswers cannot be formatted as I'd like but the above should be a table with Y valyues on the left and X values on the right) Now do the same for the other equation: y = 5x - 13 Y | X _|____ 0 | 13/5. 1 | 12/5. -13 | 0.
The rule you have described is likely a linear function. When the input is -2 and the output is 4, it means that the function relates these two values through a specific mathematical operation. To determine the exact rule, we need more data points or information about the function's form (e.g., y = mx + b for a linear function).
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We want to know for what x will Fy(x) = 30. Let's look at what Fy does: There are 3 feet in a yard, so to get from yards to feet, Fy takes the input x, and multiplies it by 3: x (yards) * 3 (feet/yard) = 3*x feet Thus we want to solve 3x = 30 Divide both sides by 3: x = 10
3x + 3x + 3x = 3* (3x) = 9x
There are an infinite number of possible rules: f(x) = 2.5*x f(x) = x2/2, f(x) = x3/10, f(x) = x4/50 etc f(x) = x+7.5, f(x) = 2x+2.5, f(x) = 3x-2.5 etc
3x^5 If these are 5 of 3x multiplied together the it must be (3x)^5 =3^5 times x^5
-3x+4y doesn't have a maximum value because you can plug in anything for x and anything for y. In fact, if you keep x=0 and you plug in larger and larger numbers for y, you get a larger and larger output--it's unbounded.