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What is the pH of 3.5 x 10 -4 M solution of KOH?

Updated: 12/21/2022
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Mseaglund

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13y ago

Best Answer

-log(3.5 X 10^-4 M)

= 3.4559

14 - 3.4559

= 10.5 pH

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Q: What is the pH of 3.5 x 10 -4 M solution of KOH?
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What is the PH of a 1.0x10 to the negative fourth power M solution of KOH?

The pH of a 1.0x10^-4 M solution of KOH is approximately 10.4. This is because KOH is a strong base that dissociates completely in water to produce hydroxide ions, which results in a basic solution.


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The pH of a 1 x 10^-5 M KOH solution would be approximately 9. For a strong base like KOH, the pH can be calculated by taking the negative logarithm of the concentration of hydroxide ions.


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The pH of a 10^-5 M KOH solution would be around 9. For a given concentration of a strong base like KOH, the pH can be calculated using the formula pH = 14 - pOH. Given that pOH = -log[OH-] and [OH-] = 10^-5 M in this case, pOH = 5. Therefore, pH = 14 - 5 = 9.


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The pH of a 0.0670 M KOH solution can be calculated using the formula pH = 14 - pOH. Since KOH dissociates completely in water to produce OH- ions, the pOH can be found by taking the negative logarithm of the hydroxide ion concentration (0.0670 M in this case). Then, pH = 14 - pOH, allowing you to determine the solution's pH.


When KOH is added to water what does the pH of the water solution do?

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Why pH electrode is dipped in saturated KOH solution?

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How does a solution of pH 7 compare to a solution of pH 10?

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