1.70
[H+] = Kw / [OH-] = 1.0*10-14 / 2.5*10-4 = 4.0*10-11 mol/L
-log[1 X 10^-4 M OH(-)] = 4 14 - 4 = 10 pH ----------------
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
HCN + H20 => CN- + H3O+ 0.45 X X Solve for X (4.0*10^-10) = x^2/0.45M x=1.34e-5= [OH] Find pOH= -log of the above number then 14-4.87=pH= 9.13
The pH of a solution can be calculated using the formula pH = 14 - pOH. Given that the pOH is 3.31, we can subtract this value from 14 to find the pH. In this case, the pH of the solution would be approximately 10.69.
To find the concentration of hydroxide ions ([OH-]) in a solution when the pH is 4.0, you can use the formula pH + pOH = 14. Since the pH is 4.0, the pOH would be 14 - 4 = 10. To convert pOH to [OH-] concentration, use the formula [OH-] = 10^(-pOH). Thus, [OH-] = 10^(-10) = 1 x 10^(-10) M.
The pOH is 6,4.
The hydroxide ion concentration of a solution with pH 5.75 can be calculated using the formula [OH-] = 10^(-pOH). First, find the pOH by subtracting the pH from 14 (pOH = 14 - pH = 14 - 5.75 = 8.25). Then, calculate [OH-] = 10^(-8.25) ≈ 5.62 x 10^(-9) mol/L.
An acidic solution will have a pOH ranging from 7 to 14
To find the pH, calculate -log[H+] using the concentration of hydrogen ions [H+]. To find the pOH, calculate -log[OH-] using the concentration of hydroxide ions [OH-]. The pH and pOH are related by the equation pH + pOH = 14 for a neutral solution.
The pH of a 0.0110 M solution of Ba(OH)2 can be calculated by finding the hydroxide ion concentration, which is double the concentration of the Ba(OH)2 solution. Therefore, [OH-] = 2 * 0.0110 M = 0.0220 M. From this, you can calculate the pOH using the formula -log[OH-], and then convert pOH to pH using the relation pH + pOH = 14.
The sum of pH and pOH is always equal to 14 in a neutral solution at 25°C. This is because pH is a measure of the concentration of H+ ions in a solution while pOH is a measure of the concentration of OH- ions. In a neutral solution, the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a sum of 14.
The pOH of a solution with an OH- concentration of 1.4 x 10^-13 M is 1.85. This is calculated by taking the negative logarithm of the OH- concentration, which is -log(1.4 x 10^-13) = 12.85, then subtracting it from 14 to find the pOH: 14 - 12.85 = 1.85.
To find the [H+] concentration in a solution with a pOH of 0.253, you first need to find the pOH of the solution which is 14 - pOH = 14 - 0.253 = 13.747. Then, you can use the relation [H+][OH-] = 1.0 x 10^-14 to calculate the [H+] concentration. [H+] = 10^-13.747 = 1.93 x 10^-14 M.
7.8
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.