12.85
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
0.20 X 420.00 = 84.00
CH3-C=O-NH2 +HCl----> CH3-C=O-OH+ NH4Cl
[H+] = Kw / [OH-] = 1.0*10-14 / 2.5*10-4 = 4.0*10-11 mol/L
1.70
12.85 is the pOH.
1.70
1.70
The concentration of OH- ions in a solution with a pOH of 4.22 is 5.24 x 10^-5 M.
To find the concentration of hydroxide ions ([OH-]) in a solution when the pH is 4.0, you can use the formula pH + pOH = 14. Since the pH is 4.0, the pOH would be 14 - 4 = 10. To convert pOH to [OH-] concentration, use the formula [OH-] = 10^(-pOH). Thus, [OH-] = 10^(-10) = 1 x 10^(-10) M.
The pOH can be calculated using the formula pOH = -log[OH-]. In this case, pOH = -log(9.0 x 10^-7) ≈ 6.05.
The pOH is the negative log of the OH- concentration. Thus, pOH = -log 2.0x10^-2pOH = 1.699 = 1.7
The pH of a solution can be calculated using the formula pH = 14 - pOH. Given that the pOH is 3.31, we can subtract this value from 14 to find the pH. In this case, the pH of the solution would be approximately 10.69.
To find the pH, calculate -log[H+] using the concentration of hydrogen ions [H+]. To find the pOH, calculate -log[OH-] using the concentration of hydroxide ions [OH-]. The pH and pOH are related by the equation pH + pOH = 14 for a neutral solution.
1.70
12.85