I'm going to answer it. y=-sqrt6x+3, y=-3rt8x+5 y=(-sqrt6x^2)+3, y=(-3rt8x^3)+5 y=-6x+3, y=-8x+5 Let's add them. 2y=-14x+8 Let's say y=0. 2(0)=-14x+8 0=-14x+8 Now we can solve for x. -14x+8=0 -14x+8-8=0-8 -14x=-8 -14x/-14=-8/-14 x=4/7 Time to see if this is right. 0=-sqrt6(4/7)+3 0=-3rt8(4/7)+5 Time to fix this. 0=(-sqrt6(4/7)^2)+3 0=(-3rt8(4/7)^3)+5 That leaves you with these two equations. 0=-6(4/7)+3 0=-8(4/7)+5 Let's combine these two. 0=-14(4/7)+8 0=-8+8 0=0 Therefore,x=4/7, and y=0.
14x = 7y+28 -7y = -14x+28 Divide all terms by -7 to find the value of y: y = 2x-4 which is now in slope intercept form
6+(-2x-8)-(-3+12x)-(4y)= 6-2x-8+3-12x-4y=1-14x-4y 1-14x=4y (1-14x)/4=y
y = b^x
y = x
y = x2 is the parent function, but it can be in the form y = ax2 + bx + c
if you need to reflect a 2-d object on a graph over its parent linear function then do as follows: (x,y) --> (-y,-x) hope that helps
y = 3*f(x + 2)
If you mean: y = 14x+2 then the slope is 14 and the y intercept is 2
(14x-2y)+(7x-3y)+(-3x) = 14x-2y+7x-3y-3x =(14+7-3)x-(2+3)y =18x-5y
2
I'm going to answer it. y=-sqrt6x+3, y=-3rt8x+5 y=(-sqrt6x^2)+3, y=(-3rt8x^3)+5 y=-6x+3, y=-8x+5 Let's add them. 2y=-14x+8 Let's say y=0. 2(0)=-14x+8 0=-14x+8 Now we can solve for x. -14x+8=0 -14x+8-8=0-8 -14x=-8 -14x/-14=-8/-14 x=4/7 Time to see if this is right. 0=-sqrt6(4/7)+3 0=-3rt8(4/7)+5 Time to fix this. 0=(-sqrt6(4/7)^2)+3 0=(-3rt8(4/7)^3)+5 That leaves you with these two equations. 0=-6(4/7)+3 0=-8(4/7)+5 Let's combine these two. 0=-14(4/7)+8 0=-8+8 0=0 Therefore,x=4/7, and y=0.
Since y=14x is a perfect linear relation, the correlation would be 1.
Y=x
y=-3x+10
y = x2
14x = 7y+28 -7y = -14x+28 Divide all terms by -7 to find the value of y: y = 2x-4 which is now in slope intercept form