34 x 28 = 34 x (20 + 8)
First partial product is: (30 + 4) x 8 = 240 + 32
Second partial product is: (30 + 4) x 20 = 600 + 80
Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
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They are 600, 240, 80 and 32.
how to find the partial products of a number
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
To find the partial products of 28 times 14, you would multiply each digit in the ones place of the second number (4) by each digit in the ones place of the first number (8), resulting in 32. Next, you would multiply each digit in the tens place of the second number (1) by each digit in the ones place of the first number (8), resulting in 8. Finally, you would add these two products together to get the final answer of 392.
The partial products are: 42 * 28 = (40 + 2)*(20 + 8) = 40*20 + 40*8 + 2*20 + 2*8 = 800 + 320 + 40 + 16