Successive numbers are obtained by dividing the previous number by 5, hence 200, 40, 8, 1.6. 0.32, 0.064,.....etc.
To determine the number of trailing zeros in (5000!), you can use the formula that counts the number of factors of 5 in the factorial. This is calculated as: [ \left\lfloor \frac{5000}{5} \right\rfloor + \left\lfloor \frac{5000}{25} \right\rfloor + \left\lfloor \frac{5000}{125} \right\rfloor + \left\lfloor \frac{5000}{625} \right\rfloor ] Calculating this gives: [ 1000 + 200 + 40 + 8 = 1248 ] Thus, (5000!) has 1248 trailing zeros.
8.525 = 341/40 or 821/40
0.2
12
8, each number is a fifth of the last.
The factors of 5000 are: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 625, 1000, 1250, 2500, 5000
8*5 = 40 8*50 = 400 8*500 = 4000 and 8*5000 = 40,000
The factors of 5000 are the numbers that can be multiplied together to result in 5000. These factors include 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000, and 5000. Factors are typically listed in pairs, with one factor being the result of dividing 5000 by the other factor.
1×5000 2×2500 4×1250 5×1000 8×625 10×500 20×250 25×200 40×125 50×100
8 x 5000 = 8 x 5 x 1000 = 40 x 1000 = 40000
800/40=200 The answer is 200.
5000+200+30+8=5238
405208 = 400000 + 5000 + 200 + 8
8, 40 and 200
40, 80, 120, 160, 200 +40 . . .
Factors of 160: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, 160.Factors of 200: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 200.GCF (160, 200) = 40