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Successive numbers are obtained by dividing the previous number by 5, hence 200, 40, 8, 1.6. 0.32, 0.064,.....etc.
To determine the number of trailing zeros in (5000!), you can use the formula that counts the number of factors of 5 in the factorial. This is calculated as: [ \left\lfloor \frac{5000}{5} \right\rfloor + \left\lfloor \frac{5000}{25} \right\rfloor + \left\lfloor \frac{5000}{125} \right\rfloor + \left\lfloor \frac{5000}{625} \right\rfloor ] Calculating this gives: [ 1000 + 200 + 40 + 8 = 1248 ] Thus, (5000!) has 1248 trailing zeros.
8.525 = 341/40 or 821/40
0.2
12