That's a Fibonacci sequence. After the first two numbers, each new number is the sum of the previous two numbers. The next number in that sequence would be 13.
It is 2, assuming the pattern is repeated as given. 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1... If the intended pattern is to continue to subtract 1 from the last number, then the 5479th digit of the pattern will be -5470.
The sequence 112358 represents the beginning of the Fibonacci series, where each number is the sum of the two preceding ones. It starts with 1, 1, 2, 3, 5, and 8. In this pattern, 1 + 1 = 2, 1 + 2 = 3, 2 + 3 = 5, and 3 + 5 = 8. The pattern continues infinitely, with each subsequent number derived from the sum of the last two.
The sequence 112358 follows the Fibonacci pattern, where each number is the sum of the two preceding numbers. Starting with 1 and 1, the next numbers are calculated as follows: 1+1=2, 1+2=3, 2+3=5, resulting in the sequence 1, 1, 2, 3, 5, 8. This pattern continues indefinitely.
There is not enough information to answer the question. The pattern could be 1 (+1) = 2 (+3) = 5 (+5) = 10 ... where the differences are the odd integers, or 1 (+1) = 2 (+3) = 5 (+6) = 11 ... where the differences are the triangular numbers, or 1 (+1) = 2 (+3) = 5 (+9) = 14 ... where the differences are powers of 3, or many, many other possibilities.
There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .
1:2:3:5:8:5:3:2:1
1123581358 1+1=2 1+2=3 3+5=8 5+8=13 3+5=8
It is 2, assuming the pattern is repeated as given. 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1... If the intended pattern is to continue to subtract 1 from the last number, then the 5479th digit of the pattern will be -5470.
this series increments in powers of 3 like 1+3^0=2 2+3^1=5 5+3^2=14 14+3^3=41 and so on....
You add the 2 numbers before e.g. 2+3=5
The sequence 112358 represents the beginning of the Fibonacci series, where each number is the sum of the two preceding ones. It starts with 1, 1, 2, 3, 5, and 8. In this pattern, 1 + 1 = 2, 1 + 2 = 3, 2 + 3 = 5, and 3 + 5 = 8. The pattern continues infinitely, with each subsequent number derived from the sum of the last two.
The sequence 112358 follows the Fibonacci pattern, where each number is the sum of the two preceding numbers. Starting with 1 and 1, the next numbers are calculated as follows: 1+1=2, 1+2=3, 2+3=5, resulting in the sequence 1, 1, 2, 3, 5, 8. This pattern continues indefinitely.
There is not enough information to answer the question. The pattern could be 1 (+1) = 2 (+3) = 5 (+5) = 10 ... where the differences are the odd integers, or 1 (+1) = 2 (+3) = 5 (+6) = 11 ... where the differences are the triangular numbers, or 1 (+1) = 2 (+3) = 5 (+9) = 14 ... where the differences are powers of 3, or many, many other possibilities.
0, 1, 1 (0+1), 2 (1+1), 3 (2+1), 5 (2+3), 8 (3+5), 13(5+8), 21 (13+8), 34 (21+13),....and so on.
11
There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .
it is basically a pattern e.g. 1 2 3 4 5 6 7 8 9 10 11 1 2 1 3 1 4 1 5 1 6 3 1 4 1 5 9 2 6 5 3 5 8 9 7 9