answersLogoWhite

0

It is 2, assuming the pattern is repeated as given. 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1...

If the intended pattern is to continue to subtract 1 from the last number, then the 5479th digit of the pattern will be -5470.

User Avatar

Wiki User

14y ago

What else can I help you with?

Related Questions

What is the next number 1 to 14 2 to 16 3 to 18 4 to 20?

The next set in the pattern would be 5 to 22. The pattern is to increase the first digit by 1, second digit by 2.


What is the 2001st digit in the repeating decimal for 1 over 7?

To find the 2001st digit in the repeating decimal for 1/7, we need to understand that 1/7 is a recurring decimal with a repeating pattern of 142857. Since the pattern length is 6 digits, we divide 2001 by 6 to get the remainder, which is 1. Therefore, the 2001st digit in the repeating decimal for 1/7 is the first digit in the repeating pattern, which is 1.


What is the unit digit of 2 the power of 40?

To find the unit digit of 2 raised to the power of 40, we can observe a pattern. The unit digit of powers of 2 cycles in a pattern: 2, 4, 8, 6. Since 40 is a multiple of 4, the unit digit of 2^40 will be the fourth number in the pattern, which is 6. Thus, the unit digit of 2^40 is 6.


What is the greatest possible product of a 2 digit and a 1 digit number?

Highest 2-digit number = 99 Highest 1-digit number = 9 Highest possible sum from 2, 2-digit numbers = 198 Highest possible sum from 2, 1-digit numbers = 18


What is the rule of the pattern of 12471116?

The pattern in the sequence 12471116 involves doubling each digit and adding the previous digit. The sequence starts with 1, then 2 (1×2), followed by 4 (2×2), then 7 (4+2+1), then 11 (4+7), and continues with 16 (11+4+1). Each term builds upon the previous terms through a combination of multiplication and addition.


What is the units digit of 29 to the 57th power?

To find the units digit of (29^{57}), we can focus on the units digit of the base, which is 9. The units digits of the powers of 9 follow a pattern: (9^1 = 9), (9^2 = 81) (units digit 1), (9^3 = 729) (units digit 9), and (9^4 = 6561) (units digit 1). This pattern alternates between 9 and 1. Since (57) is odd, the units digit of (29^{57}) is the same as that of (9^{57}), which is 9.


What is the greatest product of a 2 digit number multiplied by a 1 digit number?

2 digit number


6 digit combination from 1 to 42?

There are 28706 such combinations. 5456 of these comprise three 2-digit numbers, 19008 comprise two 2-digit numbers and two 1-digit numbers, 4158 comprise one 2-digit number and four 1-digit numbers and 84 comprise six 1-digit numbers.


What is the unit’s digit in the expansion of 2 raised to 725?

The unit's digit in the expansion of 2 raised to the 725th power is 8. This can be determined by using the concept of the "unit's digit law". This law states that the units digit of a number raised to any power is the same as the units digit of the number itself. In this case, the number is 2, which has a units digit of 2, so the units digit of 2 to the 725th power is also 2. However, this is not the final answer. To get the unit's digit of 2 to the 725th power, we must use the "repeating pattern law". This law states that when a number is raised to any power, the unit's digit will follow a repeating pattern. For 2, this pattern is 8, 4, 2, 6. This means that the units digit of 2 to any power will follow this pattern, repeating every 4 powers. So, if we look at the 725th power of 2, we can see that it is in the 4th cycle of this repeating pattern. This means that the units digit of 2 to the 725th power is 8.


How many 2-digit numbers contain digit 1?

1


What is the units digit of 29 to the 57 power?

To find the units digit of (29^{57}), we can focus on the units digit of the base, which is 9. The units digits of powers of 9 follow a pattern: (9^1 = 9), (9^2 = 81) (units digit 1), (9^3 = 729) (units digit 9), and (9^4 = 6561) (units digit 1). This pattern alternates between 9 and 1. Since (57) is odd, the units digit of (29^{57}) is the same as that of (9^{57}), which is (9). Thus, the units digit of (29^{57}) is (9).


How do you find the unit digit of 312 power 6?

Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.