The sequence can be represented by two sequences whose terms alternate. One possible way the rule can be written is:
Un = mod(n,2)*(n+1)/2 + (1-mod(n,2))*(n/2)2 for n = 1, 2, 3, ...
Alternatively, there are polynomials of degree 8 or more that will fit these numbers.
Un = 4(n-1) where n = 1, 2, 3, ...
Two ways of looking at it. First is the law of adding exponents when you multiply terms. For example, 2^4 is 16, whereas 2^-4 is 1/16. Multiplying 2^4 by 2^-4 gives 2^0 when you add the exponents. But multiplying 16 by 1/16 gives 1. So 2^0 has to be 1. Another way is pattern matching. 3 to the power of 3 = 27. 3 to the power of 2 = 9. 3 to the power of 1 = 3. 3 to the power of 0 = ____ 3 to the power of –1 is 1/3. 3 to the power of –2 is 1/9. 3 to the power of –3 is 1/27. What goes in the blank ? Well follow the pattern. Every number on the right is the preivous number divided by 3. So it has to be 1. Even 0^0 is defined to be 1 and not 0.
n, n^2, n^2^2, n+1, (n+1)^2, (n+1)^2^2, n+2, ...
3-1=2 2*4=8 8*2=16 or 3-1=2 2*2=4 4*4=16
3-1=2 2x2=4 4x4=16 or 3-1=2 2*4=8 8*2=16
12 ****************************** 11, 16, 22 are the 3 numbers continuing the pattern.
2/3 × 16 = 2/3 × 16/1 = (2×16)/(3×1) = 32/3 = 10⅔
Everytime you move to the next number you add 1, then 2, then 3, etc.1+1=22+2=44+3=77+4=1111+5=1616+6=2222+7=2929+8=37
Un = 4(n-1) where n = 1, 2, 3, ...
(3 + 1)2 = 16
(4 x 3) + 2 + 1 +1 = 16
Two ways of looking at it. First is the law of adding exponents when you multiply terms. For example, 2^4 is 16, whereas 2^-4 is 1/16. Multiplying 2^4 by 2^-4 gives 2^0 when you add the exponents. But multiplying 16 by 1/16 gives 1. So 2^0 has to be 1. Another way is pattern matching. 3 to the power of 3 = 27. 3 to the power of 2 = 9. 3 to the power of 1 = 3. 3 to the power of 0 = ____ 3 to the power of –1 is 1/3. 3 to the power of –2 is 1/9. 3 to the power of –3 is 1/27. What goes in the blank ? Well follow the pattern. Every number on the right is the preivous number divided by 3. So it has to be 1. Even 0^0 is defined to be 1 and not 0.
n, n^2, n^2^2, n+1, (n+1)^2, (n+1)^2^2, n+2, ...
3-1=2 2*4=8 8*2=16 or 3-1=2 2*2=4 4*4=16
3-1=2 2x2=4 4x4=16 or 3-1=2 2*4=8 8*2=16
Add the increasing numbers by one - as in 0 1 2 3 4 5 6 etc 1 + 0 = 1 1 + 1 = 2 2 + 2 = 4 4 + 3 = 7 7 + 4 = 11 11 + 5 = 16 16 + 6 = 22
(4 + 3 + 1) x 2 = 16