You might need to indicate what the disorder is.
there are half the chance of a female and half the chance of male so probabilty in both cases is 1/2
51%
No- they do almost ALL the hunting.
the colorblindness is usually not activited in a female body but is usually seen in male
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
The mother has a 50% chance of passing the defective recessive gene to her daughters who will be carries of the disorder (like their mother).
When a female is heterozygous i.e. she possess one allele of disease , she is called carrier .
Usually female.
A female with one copy of the allele will be a carrier, but not have the disorder.
A carrier for hemophilia is a female who carries the genetic mutation for hemophilia on one of her X chromosomes, but does not exhibit symptoms of the condition herself. Carriers can pass on the gene mutation to their children, resulting in hemophilia in male offspring. Testing can confirm carrier status.
50/50 chance
In the female carrier of a sex-linked disorder, there would typically be one normal allele and one mutated allele for the gene associated with the disorder on the X chromosome. This is because females have two X chromosomes, and one copy of the X chromosome with the mutated allele can be masked by the normal allele on the other X chromosome.
Hemophilia is passed down from mother to son. It is extremely rare for a woman to have hemophilia. It is necessary, though, for a woman to be a carrier of the disorder for her son to acquire this disorder. Females have two X chromosomes whereas males only have one. When a boy is born, he takes one X chromosome from his mother and one Y chromosome from his father. Therefore, he can only get hemophilia through his mother. Example One: Mother(Carrier)+Father(Non-Affected)=50% chance of their son acquiring the disorder and 50% chance of their daughter being a carrier. Example Two: Mother(Non-Affected)+Father(Hemophiliac)=All sons will be non-affected and all daughters will be carriers.
Haemophilia is a recessive, X-based disorder. The woman in your question is a carrier, meaning she has the defective gene, but isn't bothered by it. Therefor, the woman is of the type 'Xx'. The man is of the type 'XY', not carrying the defective gene. Their children can then be: XX, xX, XY, xY. This means that their daughters won't be affected by it, but might carry it, and their sons either not carry it at all, or carry it and be haemophilic.
Hemophilia is a genetic disorder that is usually inherited in an X-linked recessive pattern. It can appear to skip a generation when a carrier female passes the gene to her son, who then expresses the disorder. However, it doesn't truly skip a generation as the gene is passed on in each generation.
Yes but there is only a 12.5 percent chance of it happening
An X linked carrier is one who carries a mutation in a gene found on the X sex chromosome. A carrier of the trait doesn't display phenotypic symptoms of the disease or mutation but can transfer the mutation in that gene to their offspring (ex: the carrier of a premutation that when transferred to the offspring via the X chromosome will cause the full mutation associated with that gene). A person could be a homozygous carrier if for instance, she were female (two X chromosomes) and carried the premutation associated with the disease. Some diseases need both alleles of the gene to be mutated. If only one allele is mutated (heterozygote) that person may be a carrier for that mutation and can thus pass on that mutation to their children.