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Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
Solubility may be measured in grams of solute per gram of SOLVENT (not solution)
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
(Micrograms per litre)/(gram molecular weight of solute) = (micromoles per litre).
No, the mass percent concentration is a ratio of the mass of the solute to the total mass of the solution, expressed as a percentage. It is calculated by dividing the mass of the solute by the mass of the solution (solute + solvent) and multiplying by 100.
Ethanol is the solvent and sucrose is the solute.
The answer is: Concentration can be expressed as grams of solute per milliliter of solvent.
10/(10 + 25) = 10/35 = about 28.6%
Sodium chloride is the solute and water is the solvent.
Molality (m) is calculated by dividing the number of moles of solute by the mass of the solvent in kilograms and is expressed in mol/kg. The formula for molality is: [ molality (m) = \frac{moles\ of\ solute}{mass\ of\ solvent\ in\ kg} ]
The amount of solute that can dissolve in a given amount of solvent is determined by the solubility of the solute in that solvent at a specific temperature. Solubility is expressed as grams of solute per 100 grams of solvent. By knowing the solubility, you can calculate how much solute can dissolve in the specified amount of solvent.
Concentration can be measured in various units depending on the solute and solvent. Common units include molarity (moles of solute per liter of solution), mass/volume percent (grams of solute per 100 mL of solution), and molality (moles of solute per kilogram of solvent). The appropriate unit depends on the specific experimental conditions and the properties of the solute and solvent.
The maximum amount of solute that can dissolve in a solvent at a given temperature is called the solubility limit. This limit is different for each solute-solvent combination and is usually described in terms of solubility in grams of solute per 100 grams of solvent.
The amount of solvent that can dissolve a given amount of solute depends on the solubility of the solute in the solvent. Solubility is a property that describes how much of a solute can dissolve in a solvent at a given temperature. It is typically expressed as grams of solute per 100 grams of solvent. It is important to note that solubility can vary for different solutes and solvents.
To prepare 160 grams of potassium acetate with 5% w/w concentration, you will need 8 grams of potassium acetate (160 grams x 5% = 8 grams). Since potassium acetate is the solute in this case, you only need to consider the weight of the solute. The remaining weight will come from the water.
The maximum number of grams of solute that can be dissolved in a given solvent is dependent on factors such as temperature, pressure, and the specific solute-solvent system. This maximum amount is known as the solubility limit of the solute in that particular solvent.