The area is not sufficient information to determine the perimeter.
First of all, there is no reason to suppose that the area is rectangular as opposed to circular or triangular or some other simple or complicated shape. So, all that can be said is that the perimeter is greater than 178.97 feet, a perimeter that is attained when the area is a circle.
If the area is a rectangle, it could be
25.49 ft * 100 ft so that the perimeter is approx 250.98 ft
or 2.549 ft * 1000 ft and a perimeter of 2005.10 ft
or 0.2549 ft * 10000 ft and a perimeter of 2000.51 ft
or 0.0002549 ft * 10000000 ft and a perimeter of 2000000 ft.
By making the rectangle thinner and longer, the perimeter can be increased without limit.
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The area of the enlargement is increased by (sf)2.The area of the enlargement is increased by (sf)2.The area of the enlargement is increased by (sf)2.The area of the enlargement is increased by (sf)2.
2549 squared = 6,497,401...Square root of 2549 = 50.4876222
Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
It must be a perimeter. An area measurement would a square measurement like 56cm². ■
Even if you knew how many sides the polygon has, you stillcould not calculate its perimeter with that much information.Examples:-- An equilateral triangle with area of 20 has perimeter of 20.3885 .-- A square with area of 20 has perimeter of 17.889(rounded).-- A rectangle with area of 20 can have any perimeter more than 17.889 .4 by 5 . . . . area = 20, perimeter = 182 by 10 . . . area = 20, perimeter = 241 by 20 . . . area = 20, perimeter = 42..etc.