If the perimeter is already measured in inches, there is nothing to convert. There are 18 inches in a perimeter of 18 inches.
That depends on the dimensions !... A 1 x 18 rectangle has a perimeter of 38 ! A 2 x 9 rectangle has a perimeter of 22 ! A 3 x 6 rectangle has a perimeter of 18 !
If the octagon is not regular, the perimeter could have any value greater than 18 inches. If it is regular, then the perimeter is 8*18 = 144 inches.
Perimeter of the rectangle 24+18+24+18 = 84DC
That will depend on its dimensions of which none have been given but if they are 2 by 9 then its perimeter is 22 cm or if they are 3 by 6 then its perimeter is 18 cm
If the perimeter is already measured in inches, there is nothing to convert. There are 18 inches in a perimeter of 18 inches.
That depends on the dimensions !... A 1 x 18 rectangle has a perimeter of 38 ! A 2 x 9 rectangle has a perimeter of 22 ! A 3 x 6 rectangle has a perimeter of 18 !
yes, for example: a 4 by 5 rectangle has an area of 20 and a perimeter of 18 a 2 by 7 rectangle has an area of 14 and a perimeter of 18 they both have a perimeter of 18
If the octagon is not regular, the perimeter could have any value greater than 18 inches. If it is regular, then the perimeter is 8*18 = 144 inches.
Yes, it can because a 3 by 6 rectangle has the perimeter of 18 and has the area of 18! :)
Perimeter of the rectangle 24+18+24+18 = 84DC
Given a perimeter of 18 units, the resulting altitude is 5.2 (5.19615) units.
That will depend on its dimensions of which none have been given but if they are 2 by 9 then its perimeter is 22 cm or if they are 3 by 6 then its perimeter is 18 cm
The square root of 324 is 18 so the perimeter must be 4*18 = 72 cm
The square root of 324 is 18 and 4*18 = 72 units of measurement which is the perimeter of the square.
For a given perimeter, the greatest possible area is enclosed by a circle.A circle with a circumference of 18 has a diameter of (18/pi) and a radius of (9/pi).Its area is (pi R2) = (pi 92/pi2) = 81/pi = 25.78 (rounded)So an area of 42 cannot be enclosed by a perimeter of 18.
P = 18'