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What is the longitude and latitude of New Hampshire?
Latitude: 42°42′N to 45°18′NLongitude: 70°36′W to 72°33′W
What is the country code and area code of Malindi Kenya?
The country code and area code of Malindi, Kenya is 254, (0)42.
Trevor covered a cylindrical can with paper for a project The can is 18 centimeters tall and has a 5 centimeter radius Which is closest to the minimum amount of paper Trevor needed to cover the enti?
The minimum amount of paper Trevor needed to cover the entire cylindrical can is the lateral surface area of the cylinder. The lateral surface area of a cylinder can be calculated using the formula 2πrh, where r is the radius (5 cm) and h is the height (18 cm) of the cylinder. So, the minimum amount of paper needed is approximately 565.49 square centimeters.
Why is dry ice used?
The GCF of 18 and 42 is 6. 6 goes into 18 3 times and into 42 7timesTo find the GCF, you can list the factors of each number:The factors of 18 are 1, 2, 3, 6, 9, and 18The factors of 42 are 1, 2, 3, 6, 7, 14, 21, and 48The greatest factor they have in common is 6, so 6 is theGCF.The GCF is 6.
What is the longitude and latitude for medford Oregon US?
Latitude: 42°N to 46°18′NLongitude: 116°28′W to 124°38′W
How do you find the area and perimeter of 42 centimeters wide and 14 centimeters?
Assuming that it's a rectangle then:- Area = 42*14 = 588 square cm Perimeter = 42+42+14+14 = 112 cm
What is the area and the perimeter 7cm by 6cm?
Area 42 cm2, perimeter 26 cm.
What is the perimeter of a rhombus with an area of 42 and an altitude of 6?
28
If A circle and rectangle have the same area the circle has a diameter of 42 centimeters and rectangle has a width of 18 centimeters find the perimeter of the rectangle?
Area of circle = pi*212 = 1385.44236 square cm Area of rectangle = 1385.44236 square cm Lenght of rectangle = 1385.44236/18 = 76.96902 cm Perimeter of rectangle = 2(76.96902)+2(18) = 189.93804 cm
What is the area of a regular hexagon if the perimeter is 42 inches?
The area is about 127.3 square inches.
What is the area if the perimeter of the square is 168 inches?
Perimeter = 168 inches so 4*length of side = 168 inches Length of side = 168/4 = 42 inches So area = 42*42 = 1764 square inches.
What is the area of a 42 cm perimeter cube?
That depends how you define the perimeter for a cube. The term perimeter is usually used for plane figures, not for 3D solids.
What is the perimeter for a polygon that's area is 20sq. units?
Even if you knew how many sides the polygon has, you stillcould not calculate its perimeter with that much information.Examples:-- An equilateral triangle with area of 20 has perimeter of 20.3885 .-- A square with area of 20 has perimeter of 17.889(rounded).-- A rectangle with area of 20 can have any perimeter more than 17.889 .4 by 5 . . . . area = 20, perimeter = 182 by 10 . . . area = 20, perimeter = 241 by 20 . . . area = 20, perimeter = 42..etc.
What is the relationship between perimeter and area?
Perimeter is the distance AROUND any particular object where area is the amount of space inside the object (2dimentional). Let's say you have a yard 10 feet long, by 11 feet wide. The perimeter is the distance AROUND your yard or 10+10+11+11 = 42ft The AREA is the amount of space inside or L*W or 10*11 = 110ft^2 Suppose I change the dimensions of the yard without changing its perimeter (42 ft) and see what happens to the area. Suppose the length and width are 20ft and 1 ft respectively. The perimeter is still 20+1+20+1=42. The area however is 20X1 =20 ft2 Now if we take the yard to be a square one of 10.5 ft side then the perimeter still remains 42 ft. but the area becomes 110.25 ft2. Now suppose I assume that the perimeter of a circle is 42 ft. What will the area of such a circle be? Now we know that the circumference of a circle is 2x3.14(pi)Xr = 42 ft. Therefore r = 6.687 ft. r2= 44.715 ft2 therefore area of the circle is 4xpixr2= 561.63 ft 2. Thus we can deduce that given a known perimeter a circular shape has or occupies the largest area. What happens if the shape is irregular? Say a irregular polygon? Would my deduction that the cicrular shape has the largest area remain valid?
Is it possible to have a perimeter of 46 and an area of 42 as a rectangle?
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
What is the largest and smallest perimeter possible for a rectangle with a area of 42?
Largest = 86, Smallest 26
What happens to the perimeter of a rectangle when its length and width are quadrupled?
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
