2*L + 2*W = 30m L<2*W So, 2*L + L < 30m L < 10m
30 meters (7.5m x 4 sides = 30m)
An area cannot be 30m since that is a linear measure, not the measure of an area. The lowest perimeter, for an area is attained by a circle. So for an area of 30 m2 this was attained by a circle of radius R, then πR2 = 30 so that R2 = 30/π and R = sqrt(30/π) The perimeter = 2*π*R = 2*π*sqrt(30/π) = 2*sqrt(30*π) = 19.42 metres
No
55 m = 60.15 yd
The perimeter of the hexagon will be 30m (5m x 6 edges = 6 x 5 = 30m)
4*7.5 = 30m
Perimeter = 12+12+3+3 = 30m
(45 + 55) x 2 ie 200 m
2*L + 2*W = 30m L<2*W So, 2*L + L < 30m L < 10m
The dimensions of the rectangular lot are: 30m by 15m
30 meters (7.5m x 4 sides = 30m)
7.5m times the number of sides. if it's a rectangle for example, 7.5 x 4 = 30m
An area cannot be 30m since that is a linear measure, not the measure of an area. The lowest perimeter, for an area is attained by a circle. So for an area of 30 m2 this was attained by a circle of radius R, then πR2 = 30 so that R2 = 30/π and R = sqrt(30/π) The perimeter = 2*π*R = 2*π*sqrt(30/π) = 2*sqrt(30*π) = 19.42 metres
length = 30m width = 18m
To find this answer, use the perimeter formula for a rectangle and plug in the numbers. (l+w)(2) (7.5+7.5)(2) 15(2) 30m
No