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The dimensions of the rectangular lot are: 30m by 15m

Q: What are the dimensions of rectangular lot if the perimeter is 90m and the area is 450m2?

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66' x 3.27'

18 and 8

The answer depends entirely on how the dimensions change. It is possible to change the dimensions without changing the perimeter. It is also possible to change the dimensions without changing the area. (And it is possible to change the area without changing the perimeter.)

When linear dimensions are multiplied by 'K', - perimeter is also multiplied by 'K' - area is multiplied by K2 - volume is multiplied by K3

The dimensions can be 4 units by 4 units

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By halving its perimeter and using the quadratic equation formula.

66' x 3.27'

18 and 8

The dimensions are 7 by 12 meters Check: perimeter = 2*(7+12) = 38 meters and area = 7*12 = 84 square meters

You shoulda done your homework.

area 63 and perimeter is 32

what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters

The answer depends entirely on how the dimensions change. It is possible to change the dimensions without changing the perimeter. It is also possible to change the dimensions without changing the area. (And it is possible to change the area without changing the perimeter.)

The rectangle with the most area for a given perimeter is the square.Build the room square, with sides of 94-ft. The area is 8,836 square ft.

Area is quadrupled (*4) and perimeter is doubled.

It is not possible to answer this question without knowing the shape of the field - circular, triangular, rectangular, etc.

It is impossible to answer the question without knowing what the "64 feet" refers to. The perimeter, or a misstated measure of area.