3+3+7+7 = 20 inches
How many triangles exist with the given side lengths 3in, 4in, 2in
Perimeter = 2*(4ft 10in+6ft 4in) = 22ft 4in
The dimensions given fit that of a right angle triangle
6 sqin
20 in
3+3+7+7 = 20 inches
How many triangles exist with the given side lengths 3in, 4in, 2in
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
If that's a rectangle, the perimeter is 24 inches and the area is 27 square inches.
what is the volume of the rectacgular solid 2in,5in,3in.
Yes it's closer to it
Perimeter = 2*(4ft 10in+6ft 4in) = 22ft 4in
136 in.
4+4+6+5 = 19 inches is the perimeter
The dimensions given fit that of a right angle triangle
3in if the person is nice at braidind but commonly 4in.