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Q: Find the perimeter of the trapezoid below 4in 4in 6in 5in?

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C = 25.13 inches.

The volume is 96 cubic inches.

50.26548 sq. inches.

find the volume of the largest pyramid which can be cut from a rectangular parallelepiped whose edges are 2in. by 3in. by 4in. discuss fully

136 in.

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Perimeter = 2*(4ft 10in+6ft 4in) = 22ft 4in

19 in

Area of a trapezoid = 0.5*(sum of parallel sides)*height

2(3+4) = 14 inches

4 + 7 x 2 = 22 inches

6*(5ft 4 in) = 6*5ft + 6*4in = 30 ft + 24 in = 30 ft + 2 ft = 32 ft.

C = 25.13 inches.

it is not 4in it is 1/4in long

4in is less than 1 ft so 4in is a fraction of a foot 4/12 = 1/3 4in = 1/3ft = .33 ft

64in.

Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.

No because 4ft 4in is equal to 52in

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