Perimeter = 2*(40m + 5m) = 2*45m = 90m
The lengths of two sides are not enough to determine the perimeter of a triangle: Either the third side or else the angle between the two given sides is also needed. If two of the sides are 10m and 25m, then the third side can be anything between 15m and 35m, and the perimeter can be anything between 45m and 70m.
Let the length be 2x+7 and the width be x: 2(length+width) = perimeter 2(2x+7+x) = 128 4x+14+2x = 128 4x+2x = 128-14 6x = 114 x = 19 Therefore: length = 45m and width = 19m Check: 45+45+19+19 = 128m
-45m + 68 = 84m - 61 39m = 7 m = 7/39
No
Perimeter = 2*(40m + 5m) = 2*45m = 90m
Perimeter = 2*(40m + 5m) = 2*45m = 90m
The GCF is 15m.
The lengths of two sides are not enough to determine the perimeter of a triangle: Either the third side or else the angle between the two given sides is also needed. If two of the sides are 10m and 25m, then the third side can be anything between 15m and 35m, and the perimeter can be anything between 45m and 70m.
15m waves, sometimes 45m, possibly hurricanes, water tornadoes, and a lot more.
It is: 50+45+50+45 = 190m
(45 + 55) x 2 ie 200 m
It is 2*(25 + 45) = 2*70 = 140 metres.
Well, darling, the area of a rectangle is calculated by multiplying its length by its width. In this case, the rectangle is 4.5 meters long and 10 meters wide, so the area would be 45 square meters. So, go ahead and strut your stuff in that 45 square meters of space!
Let the length be 2x+7 and the width be x: 2(length+width) = perimeter 2(2x+7+x) = 128 4x+14+2x = 128 4x+2x = 128-14 6x = 114 x = 19 Therefore: length = 45m and width = 19m Check: 45+45+19+19 = 128m
17.555 is equal to 177.555 X square X breadth X with = comes to 177.555
45m means 45 million so 45,000,000 45000 is 45k