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Anything from the smallest possible width to just under 35 feet. ie 0<width<35 feet
Perimeter = 15+15+35+35 = 100 cm
220 ft
Let the length be x and the width is 20:- 2(x+20) = 110 2x+40 = 110 Subtract 40 from both sides and then divide both sides by 2 to find the width:- x = 35 feet which is the length Check: 2(35+20) = 110 feet which is the perimeter
To draw a rectangle with an area of 35 square units and a perimeter of 35 units, you can use the formulas for area (A = length × width) and perimeter (P = 2(length + width)). Let the length be ( l ) and width be ( w ). From the area, you get ( lw = 35 ), and from the perimeter, ( 2(l + w) = 35 ) or ( l + w = 17.5 ). Solving these equations simultaneously, you can find suitable dimensions, such as ( l = 10 ) units and ( w = 3.5 ) units or ( l = 7 ) units and ( w = 5 ) units.