Anything from the smallest possible width to just under 35 feet. ie 0<width<35 feet
Perimeter = 15+15+35+35 = 100 cm
Let the length be x and the width is 20:- 2(x+20) = 110 2x+40 = 110 Subtract 40 from both sides and then divide both sides by 2 to find the width:- x = 35 feet which is the length Check: 2(35+20) = 110 feet which is the perimeter
220 ft
Area: 19*35 = 665 square feet
The width of the rectangle is 7 feet. The lengthe of the rectangle is 35 feet.
Anything from the smallest possible width to just under 35 feet. ie 0<width<35 feet
Perimeter = 15+15+35+35 = 100 cm
35 mm
35 and 28
Perimeter = 24 inches Area = 35 square inches
Perimeter:20 inches Area:35
the answer is 11 sq cm
The rectangle is 35 square feet, which would be 5,040 square inches
Let the length be x and the width is 20:- 2(x+20) = 110 2x+40 = 110 Subtract 40 from both sides and then divide both sides by 2 to find the width:- x = 35 feet which is the length Check: 2(35+20) = 110 feet which is the perimeter
220 ft
=P = 2(12.0 + 5.50)==P = 35=